Draw the structures of the products, showing stereochemistry where relevant. 3. a) 1-methylcyclohexene HBr Br2 1-methylcyclohexene Br2 1-methylcyclohexene H2O 4. When bromine adds to the double bond in cyclohexene, the resulting dibromide is trans. This stereochemistry is due to: a) The intermediate bromonium ion d) Markovnikov's rule b) the intermediate carbocation d) IUPAC rules

Organic Chemistry
8th Edition
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Chapter6: Reactions Of Alkenes
Section: Chapter Questions
Problem 6.49P
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3. Draw the structures of the products, showing stereochemistry where relevant.
a)
1-methylcyclohexene
HBr
b)
Br2
1-methylcyclohexene
Br2
1-methylcyclohexene
→
H2O
4. When bromine adds to the double bond in cyclohexene, the resulting dibromide
is trans. This stereochemistry is due to:
a) The intermediate bromonium ion
d) Markovnikov's rule
b) the intermediate carbocation
d) IUPAC rules
Transcribed Image Text:3. Draw the structures of the products, showing stereochemistry where relevant. a) 1-methylcyclohexene HBr b) Br2 1-methylcyclohexene Br2 1-methylcyclohexene → H2O 4. When bromine adds to the double bond in cyclohexene, the resulting dibromide is trans. This stereochemistry is due to: a) The intermediate bromonium ion d) Markovnikov's rule b) the intermediate carbocation d) IUPAC rules
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