Problem 01: For the following parallel network, the supply voltage E = 200VZ30° with 250 rad/s as shown inFigure 01:R4EL,X = 36 2L X12Xu墓。X C,X4 = 40 2FC,C木X。Figure 01Calculate the following in extra pages which must be attached with the assignment.Also, fill in blank of following:(a) If I = 9.25AZ-26.31°,12-2222. 22 µF(i) The value of R1 =(ii) The value of C =(b) If I2 = 4.47AZ-33.43°,20 2160 mH(i) The value of R2 =(ii) The value of L2 =(c) If I3 = 11.09AZ63.69°,15-2400 pF(i) The value of R3 =(ii) The value of C3 =(d) If I4 = 7.43AZ98.2°,10260mH(i) The value of R4 =(ii) The value of L4 =(e) Calculate:(i) The voltage drop (in polar form) across the resistance R1 =(ii) The voltage drop (in polar form) across the inductance L2 =(iii) The voltage drop (in polar form) across the capacitance C3 =(iv) The voltage drop (in polar form) across the inductance L4 =(v) The total current Ir (in polar form)(vi) The power factor =(vii) Power factor is leading or lagging=.

Answered: Image /qna-images/answer/73b937b9-cdb2-4132-8f1f-2aba78282406.jpg

(e) Calculate: %3! (i) The voltage drop (in polar form) across the resistance R1 = (ii) The voltage drop (in polar form) across the inductance L2= (iii) The voltage drop (in polar form) across the capacitance C3= (iv) The voltage drop (in polar form) across the inductance L4= (v) The total current IT (in polar form) = (vi) The power factor = (vii) Power factor is leading or lagging =,

(e) Calculate: %3! (i) The voltage drop (in polar form) across the resistance R1 = (ii) The voltage drop (in polar form) across the inductance L2= (iii) The voltage drop (in polar form) across the capacitance C3= (iv) The voltage drop (in polar form) across the inductance L4= (v) The total current IT (in polar form) = (vi) The power factor = (vii) Power factor is leading or lagging =,

EBK ELECTRICAL WIRING RESIDENTIAL

19th Edition

ISBN:9781337516549

Author:Simmons

Publisher:Simmons

Chapter28: Overcurrent Protection–fuses And Circuit Breakers

Section: Chapter Questions

Problem 11R: State four possible combinations of service equipment that meet the requirements of 110.9 and 110.10...

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