e loading by an equivalent resultant force and couple moment at point. Suppose {8i - 2k) kN and F₂ = {-2i+5j- 2k} kN. (Figure 1) Determine the resultant force. Enter the z, y, and z components of the force separated by commas using three significant figures. (FR)z. (FR)y. (FR) z = Submit Part B ΠΑΠ ΑΣΦ Request Answer It vec ↑ ? kN Determine the equivalent resultant couple moment about point O. Enter the z, y, and components of the moment separated by commas using three significant figure

e loading by an equivalent resultant force and couple moment at point. Suppose {8i - 2k) kN and F₂ = {-2i+5j- 2k} kN. (Figure 1) Determine the resultant force. Enter the z, y, and z components of the force separated by commas using three significant figures. (FR)z. (FR)y. (FR) z = Submit Part B ΠΑΠ ΑΣΦ Request Answer It vec ↑ ? kN Determine the equivalent resultant couple moment about point O. Enter the z, y, and components of the moment separated by commas using three significant figure

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Replace the force system by an equivalent resultant force and couple moment at point O. Take F3 = {-200i+ 400j – 250k} N. (Figure 1) Part A Determine the resultant force. Enter the x, y, and z components of the force separated by commas using three significant figures. vec (FR)z, (FR)y, (FR); = N Figure 1 of 1 Submit Request Answer Part B F = 300 N Determine the equivalent resultant couple moment about point O. 2 m Enter the x, Y, and z components of the moment separated by commas using three significant figures. vec ? 1.5 m 1.5 m (Mr,0)2 : (MR,0)y. (Mr,0): = N. m F2 = 200 N
= 35 N, F2 = 10N, F3 =5 N, F4 =35N, F; = 40N , F6 = 10N & F7 =80N. The angles e, =15°, e; =40° , e, = 40°, es = 40 ° Find the magnitude and direction of the resultant force for the system of forces shown in the figure. Where F1 F2 F3 F1 F4 F7 Fs F6
Find the magnitude and direction of the resultant force for the system of forces shown in the figure. Where F, =30 N, F2 =30N, F3 =20 N, F1 = 55N, F; = 60N , F6 = 50N & F7 =20N. The angles e, =15°, e; =20° , e4 = 50°, eg = 15° F2 F3 F4 F1 F5 F7 F6 Enter your student ID in the box and upload your handwritten answers in the separate link provided.
Find the magnitude and direction of the resultant force for the system of forces shown in the figure. Where F1 =15 N, F2 =5N, F3 =25 N, F4 = 15N, F; = 20N , Fg = 10N & F7 =30N. The angles e, =15°, ez =40° , E4 = 50°, O6 = 15° F2 F3 F4 + Fs F7 F6
If the component of a force along x-axis is Fx = 20 kN and along y-axis is Fy = 30 kN, and if “t” is an axis making an angle of 30o in the counter clockwise direction with respect to x-axis, what would be the components of this force Ft and Fn along the orthogonal axes “t” and “n”, respectively? Select one: Ft = 2.32 kN and Fn = 35.98 kN Ft = 15.98 kN and Fn = 32.32 kN Ft = 35.98 kN and Fn = 2.32 kN Ft = 32.32 kN and Fn =15.98 kN
Question 2 Find the moment of the force about each coordinate axis (x, y, and z). Then determine the moment of the force about line AO. Mx = 72 Nm 2; My = 108 Nm G; Mz=96 Nm 6 A (0,6,4)m - OR - M. A MA - { l19.1je 79.4 è 3 Nm B(8,0.6)m
Find the magnitude and direction of the resultant force for the system of forces shown in the figure. Where F, -30 N, F2 =5N, F3 =30 N, F4 30N, Fs = 30N & F6 - 70N. The angles e, =15, e; =35, 04 = 20°, e, = 25• (Enter only the values in the boxes by referring the units given in bracket) F2 F6 Fs (1) The horizontal component EH of the given system is (unit is in N) (2) The vertical component EV of the given system is (unit is in N) = (3) The resultant of the given force system is (unit in N) = (4) The direction of Resultant is (in") =
Situation 1- For the forces shown in the Figure AP-4.1: 1. Determine the X-component of P= 300 N A the resultant force in Newtons. Answer: 185.12 N 2. Determine the Y-component of the resultant force in Newtons. Answer: 117.37 N 3. Determine the moment about point O due to forces, in N-m. Answer: 107.87 N-m 0.2 m BI R= 100 N Q = 150 N 0.2 m Figure AP-4.1
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Replace the loading system (Figure 1) by an equivalent resultant force and couple moment acting at point O. Assume F₁ 110 N, F₂ = 190 N, and M₂ = 75 N·m. Figure x 0.3 m 068 Part A FR = Submit 0.5 m Part B F2₂ Determine the resultant force. Enter the x, y and z components of the resultant force separated by commas. Expre three significant figures. Previous Answers < 1 of 1 0.4 m Mc N 4 Determine the couple moment acting at point O. Enter the x, y and z components of the couple moment separated by commas. Express you meters to three significant figures.
HOME WORK 3 Determine the resultant force at A. for the figure below Hint : 1- Find the position of all points A,B,C (x, y, z) 2- Find FAR and FAC 3- Find |raR| and Iracl 4- Find FAR = F UAB and FAC = F UAC 5- Finally find R and a, B,Y 3m Fc= 500N FB= 500N 3m 5m 3m B 4m 2m 5m
14. Use the same diagram for problems 14 to 19. A force F = 800 N, has its line of action in the direction from point A to point B, as shown in the figure below. Express the force F as a Cartesian vector. 2 m F- 800 N A .. 3 m 12 m •D 800 (2,9.3) (2,-9,-3) (-2,9.5) 800 A) V94 C) V94 800 B) 800 V94 (-2,9,-3) D) V94 15. Determine the components of the force F parallel to axis AD. -64 A) V94 -64 C) V94 (4,3.5) -64 B) V94 -4, 3, –5) D) 16. Determine the components of the force F perpendicular to axis AD. A) (191.43, 722.82,280.55) B) (191.43, – 722.82, –280.55) (-191.43, – 722.82, –280.55) D) (-191.43,– 722.82, 280.55) C) 17. What is the angle between OB and OD? A) 126.87° B) 127.65° C) 124.98° D) 125.84° 18. Determine the moment of the force F about point O. 800 A) M, = (12,6,-10) 800 C) M, = V94 :(-12,-6,-10) (-12,-6,10) V94 800 -10) 800 D) M, = 194 B) M, = 12,-6, 194 19. What is the moment of the force F about the axis OC? 990 A) Molloc =- (4.8.0) 960 C) Molloc = V94 890 D) Molloc = V94…