Elite (n = 16) University (n = 13) Quality x S x S Sprint 27.3 0.7 26.0 1.5 speed (km/hr) Peak heart 192.0 6.0 193.0 6.0 rate (bpm) Intermittent 1160 191 781 129 recovery test (m) Carry out the significance tests using α = 0.05. Report the test statistics and P-values and write a short summary of your conclusion. (Software gives k = 16.2, 25.8, and 26.2, respectively.)

/transcript Call centers typically have high turnover. The director of human resources for a large bank has compiled data on about 70 former employees at one of the bank's call centers. The accompanying table shows this data. In writing an article about call center working conditions, a reporter has claimed that the average tenure is no more than two years. Formulate and test a hypothesis using these data to determine if this claim can be disputed. Use a level of significance of 0.05. Click the icon to view the call center data. Is there sufficient evidence at the 0.05 level of significance that the average tenure is no more than two years? Determine the null hypothesis, Ho, and the alternative hypothesis, H₁. Ho ... H₁: (Type whole numbers.) le Le

You are performing a two-tailed test with test statistic z=-1.723, find the p-value accurate to 4 decimal places.p-value =

During the first day of classes for the second semester, the Statistics and Probability teacher of your class conducted a test to a random sample of 100 students. They got a mean score of 80.68 with a population standard deviation of 12. The population mean is 78.37. Use 0.05 level of significance. Find the Z-value.

As the director of a research laboratory you are paid to decide if there is a significantdifference between the mean values of two sets of data obtained by two different scientists, asenior scientist and one recently hired. Use 95% CL. (t at df = 10 is 2.23)• Data of Senior Scientist: x mean = 24.66% with s = 0.06% for n = 5• Data of the New Kid: x mean = 24.55% with s = 0.10% for n = 7

korynn is calculating the variability in her data by measuring the average distance of scores from the mean. korynn is calculating the: standard deviation  mode range median

You are conducting a study to see if the average male life expectancy is significantly less than 98. Thus you are performing a left-tailed test. Your sample data produce the test statistic z = - 2.572 . Find the p-value, accurate to 4 decimal places. p-value =

A tire manufacturer has a 60,000 mile warranty for tread life. The company wants to make sure the average tire lasts longer than 60,000 miles. The manufacturer tests 250 tires and finds the mean life for these tires to be 64,500 miles. What is the alternative hypothesis being tested in this example?  The proportion of tires that are worn out after 60,000 miles is greater than 1/2.  The mean tire life is equal to 64,500 miles.  The mean tire life is less than 60,000 miles.  The mean tire life is greater than 60,000 miles.

The Emotional Quotient (EQ) score on the latest version of Sirug EQ Test is transformed so as to follow a normal distribution with a mean of 110 and standard deviation of 15. Find the 96th percentile of the distribution of Emotional Quotient. Solution: Step 1: Draw a figure and represent the area.  Step 2: Find the z value.  Step 3: Solution to find the 96th percentile.

The data set of the diameters of the metal cylinders manufactured an automatic machine has sample size of n=28, mean of x= 49.94 mm and std. of S = 0.15 mm. Expected diameter of metal cylinder is µ = 50.00 mm. Can we be 95% confident that machine calibrated properly?