Equations: • Π1 П₁ = 0.8л +0.25 л₁ + 0.15П₂ • П₂ = 0.15П。 +0.7л₁ +0.05π₂ π 2 • π3 = 0.05 лo +0.05π₁ + 0.8π₂ • Π3 + π + π = 0 1

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section: Chapter Questions
Problem 28RE
Question

solve and replace in the equations

Equations:
• Π1
П₁ = 0.8л +0.25 л₁ + 0.15П₂
• П₂ = 0.15П。 +0.7л₁ +0.05π₂
π 2
• π3 =
0.05 лo +0.05π₁ + 0.8π₂
• Π3 + π + π = 0
1
Transcribed Image Text:Equations: • Π1 П₁ = 0.8л +0.25 л₁ + 0.15П₂ • П₂ = 0.15П。 +0.7л₁ +0.05π₂ π 2 • π3 = 0.05 лo +0.05π₁ + 0.8π₂ • Π3 + π + π = 0 1
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