Evaluate (130 points); Use 3 decimal places. 1. The annual load of a substation is given in the following table. During each month, the power is assumed constant at an average value. Find the (a) average load and (b) the annual load factor. Annual System Load January February March 8 Y 4 April May 26 2 6 2, Tv June 12 sing July 14 phas August 14 idea September 10 imp October 8 5Y5 November December 68 6 ma del
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- Table Q2a Time (hours) 0-6 6-12 12-14 14-18 18-24 Load (MW) 45 90 135 150 75 Referring to the Table Q2a; i) Draw the load curve and the load duration curve [Use the graph paper provided] ii) Indicate the base load and the peak load on the graph. Determine the values for both loads. iii) Choose the suitable generating units to supply the load and list their operating schedules. Later, compute the total installed capacity. iv) Calculate the load factor and the plant capacity factor. Discuss the impact on the operating schedule if the plant capacity factor increases to 0.9.The transformer secondary is connected in star supplies power to purely resistive load with one ammeter and wattmeter connected as shown in figure below. Reading of ammeter is 9 A and that of wattmeter is 810 W. The line-to-line voltage are balanced. The value of Ris _. (Consider harmonics up to third harmonics). eeeee eeeee W eeeee ww vor RPower factor correction is usually done by adding _________ to the load circuit.Select the correct response:a. switchb. capacitorc. inductive loads
- What is the main direct cause of reactive power in AC system?A. Resistance of transmission linesB. Inductance and capacitance in the loadsC. Ideal transformer connected in the systemD. Power produced by generatorThe peak load on a 50 MW power station is 39 MW. It supplies power through for transformers whose connected loads are 17, 12,9 and 10 MW. The maximum demands on these transformers are 15, 10, 8 and 9 MW respectively. The annual load factor is 50% and the plant is operating for 65% of the period in a year. 102. The average load on the station is (A) 50000 kW (C) 39000 kW (B) 19500 kW (D) 48000 kW. 103. The energy supplied per year is (A) 438 x 106 kWh (C) 170.82 x 106 kWh (B) 341.64 x 106 kWh (D) 420.48 x 106 kWh.An alternator with internal vallage of 125, p.u. and synchronous reactance of 0.4 p.u. is connected by a transmission line of reactance 0.1 p.u. c a synchronous meto having synchronous reactance 2.35 p u. and internal voltage of 0.85/6, p.u. If the real power supplied by the alternator is D 806 p... than (8, & is. degrees. (Round off to 2 decimal places) (Machines are of non-salient typa. Naglact resistances)
- A low voltage distribution transformer feeds two different loads with a three-phase line. The nominal voltage of the line is 400 Volt. The total length of the feeder is 500 m. The distance from the transformer to these loads is 140 m and 340 m, respectively. Their consumption is 11 kVA with a 0.8 lagging power factor and 10 kW with a 0.8 lagging power factor, respectively. The feeder's cross-section is 15 mm2 and the feeder's conductivity is 56 m/ohm.mm2. Find the following information. The distance from the transformer to the maximum voltage drop point is m The maximum voltage drop is Volt The power loss between the transformer and 11 kVA load is Watt.In the system shown in Figure 1, the transformers are connected star-star with both star points grounded and the generators are connected in star with thier star points grounded. The system base is 15 MVA. The transformers all have reactances of 0.04 p.u. on this 15 MVA base. The reactances of all other elements are given in Table 1 (in 2) and the voltage levels are given in Table 2. p.u. G1 p.u. T1 jö Per-Unit Convert all values to p.u. on a 15 MVA base. Xa= p.u. Xc₂= XL = V BABE G1 2 X 9 T3 Figure 1: A section of the distribution system T1 L Table 1: Sequence reactances (2) 3 G1 L G2 0.3 0.59 0.01 4 L 9/10 10 Fault Voltage What is the voltage at bus 3 (in Volts) after the fault has occurred? Vp= V T2 5 T2 34 10/4 Table 2: Voltage bases (kV) G2 4 T3 10/9 | G2 Fault Current A three-phase fault with a fault reactance of 0.01 p.u. occurs at bus 3. Calculate the fault current flowing at the fault point in KA. Ip=-j KA SoA 10 MVA three phase load is to be served by a three phase transformer at aline voltage of 13.8 kV. The supply side voltage(line-line) is 138 kV. Varioussingle phase transformers are available in the warehouse but all havewindings with voltage ratings under 100 kV and current ratings under 250 A.Is it possible to serve the load using only three single phase transformers? Ifso, specify the three phase connections and the low and high voltage ratingsof the single phase transformers.
- In the transmission system shown in the figure above, the rated kVA of transformer 1, T1, is 1000 kVA and the rated kVA of transformer 2, T2, is 500 kVA. Transformers pu impedances are given on their rated powers. What is the real power in kWatts supplied to the load?The per unit impedance of a generator on a 60 MVA, 20 kV base is j0.09 p.u. The per unit impedance to a 100 MVA, 20 kV base will be (a.) j0.054 p.u. (c.) j 1.5 p.u. (b.) j0.54 p.u. (d.) j0.15 p.u.Can ripple factors be grater then unity . Justify?