Example: Be S If a coil conductor is connected to a 3 kQ resistor, what would be the rated voltage and current that would be measured if the north pole of the magnet is moving closer to the coil conductor and the rate of change of flux is 3 wb/s and the N AN-0 (c) number of turns is three? B Bag S I Given: N = 3 turns 3.0 ka Figure 1. (a) When this bar magnet is thrusted into the coil, the strength of the magnetic field B increases in the coil. The current induced in the coil creates another field, in the opposite I direction of the bar magnets to oppose the increase. This is one aspect of Lenz's law-induction opposes any change in flux. (b) and (c) are two other situations. Verify for yourself that the direction of the induced Bcoil shown indeed opposes the change in flux A0and that the current direction shown is consistent with = 3 wb/s dt R= 3 kn = 3 x 103 2 N Solution: e = N- dt = (3)( 3) wb = 9 V V I the right-hand rule in Attachment A.1. By following Fig. 1 (a) it can be seen that the motion of 3.0 ka the magnet makes the induced current move S N clockwise, therefore making the measured voltage positive. Conclusion: By Ohm's Law where V = e: Therefore, the rated voltage across the resistor is 9 V and the rated current passing through the resistor is 3 mA. 9 V V e I = R = 3 x 10-3A or 3 mA -= - 3= R 3х 103 0 Activity: Solve for the rated current and rated voltage, on the given figure, when the number of turns of the conductor is eight (8) and the rate of change is 4 wb/s on the given situations; (a) the south pole of the magnet is moving towards the coil conductor and (b) the south pole of the magnet is moving I 5.0 ka away from the coil conductor. Write your answers on a separate sheet of N paper and illustrate the direction of the current. Use the rubrics as your S guide in presenting your solution (refer to attachment A.2 at the next page).
Example: Be S If a coil conductor is connected to a 3 kQ resistor, what would be the rated voltage and current that would be measured if the north pole of the magnet is moving closer to the coil conductor and the rate of change of flux is 3 wb/s and the N AN-0 (c) number of turns is three? B Bag S I Given: N = 3 turns 3.0 ka Figure 1. (a) When this bar magnet is thrusted into the coil, the strength of the magnetic field B increases in the coil. The current induced in the coil creates another field, in the opposite I direction of the bar magnets to oppose the increase. This is one aspect of Lenz's law-induction opposes any change in flux. (b) and (c) are two other situations. Verify for yourself that the direction of the induced Bcoil shown indeed opposes the change in flux A0and that the current direction shown is consistent with = 3 wb/s dt R= 3 kn = 3 x 103 2 N Solution: e = N- dt = (3)( 3) wb = 9 V V I the right-hand rule in Attachment A.1. By following Fig. 1 (a) it can be seen that the motion of 3.0 ka the magnet makes the induced current move S N clockwise, therefore making the measured voltage positive. Conclusion: By Ohm's Law where V = e: Therefore, the rated voltage across the resistor is 9 V and the rated current passing through the resistor is 3 mA. 9 V V e I = R = 3 x 10-3A or 3 mA -= - 3= R 3х 103 0 Activity: Solve for the rated current and rated voltage, on the given figure, when the number of turns of the conductor is eight (8) and the rate of change is 4 wb/s on the given situations; (a) the south pole of the magnet is moving towards the coil conductor and (b) the south pole of the magnet is moving I 5.0 ka away from the coil conductor. Write your answers on a separate sheet of N paper and illustrate the direction of the current. Use the rubrics as your S guide in presenting your solution (refer to attachment A.2 at the next page).
Chapter8: Electromagnetism And Em Waves
Section: Chapter Questions
Problem 20Q: (Indicates a review question, which means it requires only a basic understanding of the material to...
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Question
Transcribed Image Text:Example:
Be
Bess
N
If a coil conductor is connected to a 3 kQ resistor, what would
be the rated voltage and current that would be measured if
the north pole of the magnet is moving closer to the coil
conductor and the rate of change of flux is 3 wb/s and the
AN-0
(c)
number of turns is three?
B
N
S
I
Given:
N = 3 turns
3.0 ka
Figure 1. (a) When this bar magnet is thrusted into the
coil, the strength of the magnetic field B increases in the
coil. The current induced in the coil creates another field,
in the opposite I direction of the bar magnets to oppose
the increase. This is one aspect of Lenz's law-induction
opposes any change in flux. (b) and (c) are two other
situations. Verify for yourself that the direction of the
induced Bcoil shown indeed opposes the change in flux
A@and that the current direction shown is consistent with
= 3 wb/s
dt
R= 3 kQ = 3 x 103 Q
N
Solution:
e = N
dt
:= (3)( 3)
wb
= 9 V
V
I
the right-hand rule in Attachment A.1.
By following Fig. 1 (a) it can
be seen that the motion of
3.0 ka
the magnet makes the
induced
current
move
S
N
clockwise, therefore making
the measured voltage
positive.
Conclusion:
By Ohm's Law where V = e:
V e
I =
R
Therefore, the rated voltage across the resistor is 9 V and
the rated current passing through the resistor is 3 mA.
9 V
3D 3х 10-3А оr 3 mA
-= - =
R
3х 103 0
Activity:
Solve for the rated current and rated voltage, on the given figure, when the
number of turns of the conductor is eight (8) and the rate of change is 4
wb/s on the given situations; (a) the south pole of the magnet is moving
towards the coil conductor and (b) the south pole of the magnet is moving
I
5.0 ka
away from the coil conductor. Write your answers on a separate sheet of
N
paper and illustrate the direction of the current. Use the rubrics as your
S
guide in presenting your solution (refer to attachment A.2 at the next page).
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