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- You are a robotics engineer working for a large tech company. For one of your artificially intelligent robots, you are looking to see if the size of the data file used to train the robot is predictive of the time the robot takes to complete a maze. You are going to collect a random sample of 9 attempts at completing the maze. You will note for each attempt the size of the data file (denoted by x, in MB) and the time (denoted by y, in seconds) to complete the maze. You will also note the product x'y of the size of the data file and the completion time for each attempt. (These products are written in the row 画 labeled "xy"). (a) Click on "Take Sample" to see the results for your random sample. Data file size, x 181.7 39.1 75.6 138.9 93.4 52.8 138.9 124.3 203.2 (in MB) Completion time, y (in seconds) Take Sample 143 371 320 201 343 435 252 264 88 ху 25,983.1 14,506.1 24,192 27,918.9 | 32,036.2 22,968 | 35,002.8 32,815.2 17,881.6 Send data to calculator Based on the data from your sample,…The data below gives the speed as measured by radar, I have a random sample of 10 vehicles traveling on I-95. Calculate the first second and third quartiles of the data. Also the time in the interquartile range Q1= Q2= Q3= IQR=Run a regression analysis on the following bivariate set of data with y as the response variable. Verify that the correlation is significant at an α=0.05. If the correlation is indeed significant, predict what value (on average) for the explanatory variable will give you a value of 43 on the response variable.
- help find t-statistic and p-value?H. : p = 0.65 and H, : p > 0.65 where p= the proportion of students who were quarantined at some point during the Fall Semester of 2020. Identify the correct explanation for a Type Il error. O Conclude the percent was higher than 65%, but it was not higher. Conclude the percent was higher than 65% and it was higher. O Did not conclude the percent was higher than 65%, but it was higher. O Did not conclude the percent was higher than 65% and it was not higher.Which value of r indicates a stronger correlation than +0.40 0.38 -0.30 -0.80 0
