F1-100 2m F2=250 A 4m F3-200 F4=150 2,5m Find the forces acting on supports A and B in the figure. 3m B
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- PS2-5 Three forces are acting on the problem. List all of the simplifications that can be used in the problem. What is the simplest problem? F₂ 45° R4. Forces F =F-20N and the third force F3 25N act on a cube with the side of a=2m. a. Find the screw driver (wrench) that is created by these forces i.e pitch, Mparallel, Mpapendicular b. Find the point of intersection of the axis of the wrench with the x-y plane. How do you check your answer is correct? G F D A B.perpendicular to the page through the point o. (Let counterclockwise torque be positive and let forces to the right and up be positive. Use the following as necessary: the forces R, Write the necessary equations of equilibrium of the object shown in the figure below. Take the origin of the torque equation about an axis RFF, and F the length l of the object; and the angle e that the object makes with the horizontal.) EF, = = 0 Fy =0 Στ. =0 Need Help? Read It
- Q5/A) From the figure below, determine the reaction force at pin C. A 000 0.6 m 10 kN 0.6 m 0.8 m 60° 0.4 m 6 kN OBA cargo ship is tied down to marine boll arts at a number of points along its length while its cargo is unloaded by a container handling crane. Each bollard is fastened to the wharf using anchor bolts. Three cables having known tension force magnitudes F, = ll0 kN.F, = 85kN.and F, 9OkNare secured to one bollard at a point A with coordinates (0.0.45 m. 0) in the x-r-: coordinate system shown in the figure part b. Each cable force is directed at an attachment point on the ship. Force F, is directed from point A to a point on the ship having coordinates (3 m, 9 m. 0) force F, is directed at a point with coordinates (6.5 m. 8.5 m. 2 m) and force F, is directed at a point with coordinates (8 m. 9 m. S m). The diameter of each anchor bolts is 4 24 mm. (a) Find the reaction forces and reaction moments at the base of the bollard. (b) Calculate the average shear stress in the anchor bolts (in the x-: plane). Assume each bolt cart ics an equal share of the total force.Determine completely the resultant of the forces acting on the step pulley in Figure 1-36. 750 lb 2 = 1- 60 - 250 lb 1250 lb Figure 1-36
- НОМE WORK 3 Determine the resultant force at A. for the figure below Hint : 1- Find the position of all points A,B.C (x, y., z) 2. Find Fas und FAC 3. Find Tanl and Iracl 4. Find FAg = F UA and Fac = F UAC 5- Finally find R and a, B.y 3m Fc= 500N FB= 500N 3m 5m 3m B 2m 4m 5m4-61 Change the force F to {200i + 400j -700k}The forces acting on the arm of an athlete doing shoulder exercises are shown in the figure. The athlete holds his arm at an angle of β=15° with the horizontal axis. Point O represents the axis of rotation in the shoulder joint, point A represents the connection point of the deltoid muscle to the humerus, point B represents the center of gravity of the arm, and point C represents the application point of the force acting on the hand. The distances between the rotation axis (O point) of the shoulder joint and the points A, B and C are a=20 cm, b =33 cm and c= 65 cm, respectively. The athlete's hand is exerted by a force of F= 150 N, which makes an angle of γ=30° with the vertical from the point C. The weight of the athlete's arm is W= 100 N. The direction of application of the Fm muscle force makes an angle of α=25° with the longitudinal axis of the arm. According to this; a) Calculate the FM muscle strength. b) Calculate the angle θ of the FJ joint reaction force with the horizontal.…
- Problem 2-16 Resolve the force Fzinto components acting along the u and v axes and detemine the magnitudes of the components. Given: F1 = 250 N F2 = 150 N e1 = 30 deg 82 = 30 deg 8z = 105 degThe forces acting on the arm of an athlete doing shoulder exercises are shown in the figure. The athlete holds his arm at an angle of β = 30° with the horizontal axis . Point O represents the axis of rotation in the shoulder joint, point A represents the connection point of the deltoid muscle to the humerus, point B represents the center of gravity of the arm, and point C represents the application point of the force acting on the hand. The distances between the rotation axis (O point) of the shoulder joint and the points A, B and C are a=22 cm , b =33 cm and c= 60 cm , respectively . A force of F= 120 N, which makes an angle of γ=30° with the vertical from the point C, acts on the athlete's hand . Weight of the athlete's armW= 80 N. The direction of application of the Fm muscle force makes an angle of α=20° with the longitudinal axis of the arm. According to this; a) Calculate the muscle strength F M b) Calculate the angle θ of the joint reaction force F J with the horizontal.…4-6 if possible