Figure 14.14 INVENTORY ON HAND Information for Problems PART PART STRUCTURE TREE 14.14, 14.15, 14.16, and 14.17 LT = lead time in weeks (1) = All quantities = 1 A A LT = 1 B 10 B(1) LT = 1 F(1)| LT = 1 D 4 C1 LT =2 D(1) LT = 1 G1 LT = 3 Hu LT = 1 F G 1 H 10 E1) LT = 1 E LT = 1 C(1) LT = 2

Practical Management Science
6th Edition
ISBN:9781337406659
Author:WINSTON, Wayne L.
Publisher:WINSTON, Wayne L.
Chapter2: Introduction To Spreadsheet Modeling
Section: Chapter Questions
Problem 20P: Julie James is opening a lemonade stand. She believes the fixed cost per week of running the stand...
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Question
You are product planner for product A (in Problem
(A part structure, lead time (weeks), and on-hand
quantities for product A are shown in Figure 14. 14. From the
information shown, generate:
a) An indented bill of material fo r product A
b) Net requirements for each part to produce I0 As in week 8
using lot-for-lot. IP).) The field service manager, Mark Moon,
has just called and told you that the requirements for B and F
should each be increased by I 0 units for his repair requi rements in
the field.
a) Prepare a list showing the quantity of each part required to produce the requirements for the service manager and the production request of I 0 Bs and Fs.                                                          b) Prepare a net requirement plan by date for the new requirements (for both production and field service), assuming that the field service manager wants his 10 units ofB and F in week 6 and the 10 production units of A in week 8.
Figure 14.14
INVENTORY
ON HAND
Information for Problems
PART
PART STRUCTURE TREE
14.14, 14.15, 14.16, and 14.17
LT = lead time in weeks
(1) = All quantities = 1
A
A LT = 1
B
10
B(1) LT = 1
F(1)| LT = 1
D
4
C1 LT =2
D(1) LT = 1
G1 LT = 3
Hu LT = 1
F
G
1
H
10
E1) LT = 1
E LT = 1 C(1) LT = 2
Transcribed Image Text:Figure 14.14 INVENTORY ON HAND Information for Problems PART PART STRUCTURE TREE 14.14, 14.15, 14.16, and 14.17 LT = lead time in weeks (1) = All quantities = 1 A A LT = 1 B 10 B(1) LT = 1 F(1)| LT = 1 D 4 C1 LT =2 D(1) LT = 1 G1 LT = 3 Hu LT = 1 F G 1 H 10 E1) LT = 1 E LT = 1 C(1) LT = 2
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