Filtered Excretion Clearance Urine Vol GFR (L/day) (ml/min) mg/ml [Urine] [Plasma] mg/ml Load Rate (ml/min) (mg/min) (mg/min) Na* 1.5 125 1.65 3.08 K* 1.5 125 1.95 0.195 1.5 125 2.65 3.5 Glu 1.5 125 0.9 www
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RENAL CALCULATIONS
Please complete the chart and show your work.
![Urine Vol
(L/day)
[Urine] [Plasma]
mg/ml
GFR
Filtered
Excretion Clearance
(ml/min) mg/ml
Rate
(mg/min)
Load
(ml/min)
(mg/min)
Na+
1.5
125
1.65
3.08
K+
1.5
125
1.95
0.195
1.5
125
2.65
3.5
ww
Glu
1.5
125
0.9
wwww](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa5b6fab4-dfde-4ec5-a3de-a1d9022f0250%2F4b0acb2b-f200-4209-b782-ecec32a5000e%2Fugcjg6_processed.jpeg&w=3840&q=75)
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- A 60-year-old woman with history of lung cancer is admitted for weakness and lethargy for 4 weeks. Her serum [Na*] is 120 mEq/L. She weighs 60 kg. Her serum osmolality is 250 mOsm/kg H2O with urine osmolality of 616 mOsm/kg H2O. The diagnosis of SIADH is made. What would be her serum [Na], if she receives 1 L of isotonic saline? A. 122 mEq/L B. 116 mEq/L C. 118 mEq/L D. 120 mEq/L E. 124 mEq/LUrine Vol (L/day) GFR (ml/min) [Urine] mg/ml [Plasma] mg/ml Filtered Load (mg/min) Excretion Rate (mg/min) Clearance (ml/min) Na+ 1.5 125 1.65 3.08 K+ 1.5 125 1.95 0.195 Cl- 1.5 125 2.65 3.5 Glu 1.5 125 0 0.9Table 3. Serum creatinine values at admission and after 12h Admission +12h SCR(mg/dL) 1.55 1.42 Using the “MDRD” (Modification of Diet in Renal Disease) equation for estimating glomerularfiltration, provided below, and the data available in the above table, calculate the patient's (a 34 year old white male) estimated glomerularfiltration rate (eGFR) at admission and 12h after admission.MDRD GFR Equation (mL/min/1.73 m2)= 175 × (Scr)-1.154 × (Age)-0.203 × (0.742 if female) × (1.212 if African American)Based on your calculated values, state whether LF’s function is normal or abnormal?Previous research suggests that patients with asthma have an increased risk for chronic kidneydisease, but the mechanisms underlying this increased risk are poorly understood. Propose one potential mechanism by which asthma might impair kidney function, and discuss how this dysfunction may impair thebody’s ability to respond to respiratory alkalosis
- Renal Calculations Urine Vol Excretion Clearance [Urine] (ml/min) mg/ml [Plasma] mg/ml GFR Filtered (L/day) Load Rate (ml/min) (mg/min) (mg/min) Na+ 1.5 125 1.65 3.08 K+ 1.5 125 1.95 0.195 CI- 1.5 125 2.65 3.5 Glu 1.5 125 0.9 w wwUrine creatinine: 190 mg/dL .Plasma creatinine: 2.5 mg/dL. 24-hour urine collection: 975 mL. C(ml/min)= (U(mg/dL)x V(mL/min) )/(P(mg/dL))36. A 3-month-old boy is brought to the emergency department because of a 2-day history of lethargy. Physical examination shows no other abnormalities. The results of laboratory studies are shown: Serum Na+ 165 mEq/L (N=139-146) CI- 130 mEq/L (N=95-105) 334 mOsmol/kg H₂O (N=282-295) Osmolality Urine 1.001 Specific gravity Osmolality 117 mOsmol/kg H₂O (N>200) He is admitted to the hospital. His urine output is increased. His serum ADH (vasopressin) concentration is 24 pg/mL (N=1-5); aldosterone and renin concentrations are within the reference ranges. The urine osmolality remains unchanged after administration of 1-deamino-8-arginine vasopressin. An MRI of the brain and pituitary gland shows no abnormalities. Ultrasonography shows normal kidneys. The most likely underlying cause of the findings in this patient is a defect in which of the following? A) Angiotensin-converting enzyme B) Aquaporin C) 11a-Hydroxylase D) Renin E) Vasopressin receptors
- Urine creatinine: 180 mg/dL . Plasma creatinine: 2.3 mg/dL . Urine output: 1.6 mL/mi Creatinine Clearance (C) = (Urine Creatinine × Urine Flow Rate) / Plasma Creatinine What is CA 24hr increase of GFR from 90ml/min to 120 ml/min because of a change of filtration fraction from 0.15 to 0.2 with no change of 24 hr water and sodium intake is expected to cause the following: O A. Decrease renal oxygen consumption OB. Decrease body water OC. Decrease renal plasma flow OD. Decrease volume of urineA patient comes to your medical practice with complaints of low urine output (not peeing). You use inulin to calculate the glomerular filtration rate (GFR) using the following information: Plasma level (P – constant over 24 hours): 10 mg/mL inulin. Urine sample (U): 144 mg inulin/mL urine. Urine formation (V): 10 mL/min. Using the fromula GFR=V ✕ U/P, you calculate a GFR of ... A) 144mL/min.. B) 14400 mL/min. C) 144 min./mL. D) 144 g mannitol/min.
- A 68-year old woman presents with hypertension and oliguria. A CT of the abdomen reveals a hypoplastic left kidney. based on the following laboratory data which of the following is her estimated RPF? Renal artery p-amino hippuric acid (PAH) = 6mg/dL Renal vein PAH = 0.6mg/dL urinary PAH = 25mg/mL urine flow= 1.5mL/min hematocrit = 40%Assuming a urine flow rate of 1 ml/minute which of the following most likely represents the rate of Na+ excretion (in mEq/min) in this man? a. 0.10 b. 1.0 c. 10 d. 100 e. 100if normal GFR is 125ml/minute, how long does it take to produce 1 liter of urine assuming 99% renal reabsorption
