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- Purple flowers are dominant to white flowers. Identify the phenotypefor the following genotype Ff, FF, ff and determine if the genotype is heterozygous or homozygous. * For each row, you should select two columns. Purple flowers White flowers Heterozygous Homozygous Ff FF ff Brown eyes are dominant to blue eyes. Identify the phenotype for the following genotype BB, Bb, bb and determine if the genotype is heterozygous or homozygous. * 口 ロ口Punnett Squares Practice Monohybrid Crosses DIRECTIONS: All these genetic probiems deal with pea plants and heir traits. Use the following kay for ail problems. Put the gametes for the 1st parent of each cross along the top, and the gametes for the 2nd parent along the left side. T= Tall ( = Short S= Smooth Seed = Wrinkled Seed G= Green Pod Y= Yellow Seed P= Purple Flower g= Yellow Pod 2. TT x TE y- Green Seed A= White Flower 1. PP x PA 3. Sa x Sa 4. yy x yy 5. Gg x Gg PP PA AP YY Yy 99 GG Gg gg SS Sa sa 8. heterozygous yellow seed x green seed TT TE 6. hybrid tall x short Te x t 7. purebrid tall x short TT x 9. hybrid green pod x hybrid green pod 10. hybrid tall x purebred tall YY Yy 99 13. heterozygous purple flowers x TT T TT TE GG Gg gg TT Te 11. purebred purple flowers x white flowers 12. hybrid purple flowers x white flowers 14. hybrid smooth seeds x hybrid smooth seeds 15. short plant x short plant white flowers PP PA AP PP PA AA phenotype ratios: PP PA AE Ss Se TT TE Purple…Make sure to include (genotypic ratios) For part A) make sure to have table or the phenotypic or genotypic ratios 5. In garden peas, green pod (P) is dominant to yellow pod (p) and tall stemmed (T) plants are dominant to short stemmed plants (t). Please give the genotypic and phenotypic ratios from the following crosses. a) Homozygous green pod homozygous tall stemmed plant crossed with a yellow pod (homozygous) short stemmed (homozygous) plant. b) Homozygous green pod homozygous tall stemmed plant crossed with a heterozygous green pod heterozygous tall stemmed plant. c) Heterozygous green pod heterozygous tall stemmed plant crossed with a heterozygous green pod heterozygous tall stemmed plant. d) Heterozygous green pod homozygous tall stemmed plant crossed with a yellow pod (homozygous) homozygous tall stemmed plant. These are dihybrid crosses. 7. In pea plants, flower colour and pollen shape are located on the same chromosome. A plant with purple flowers and…
- 5 & :56M ******* 24 DIHYBRID CROSSES DRV 0 Stv T alı A @ zladenA 9160p2-id2 bns obidalbaneoviene da II\ MOD YR 21 $59A ... Create a dihybrid cross and determine the expected phenotypic percentages of the offspring of two corn plants both of which are heterozygous for colour and texture (RrTt X RrTt). Don't forget to include clear let statements, and follow the all six steps taught on solving genetics problems. insig moni nellog: bna. zoomMonohybrid Crosses and Punnett Squares Punnett squares are diagrams that can be used to predict the offspring that could result from combination of the gametes produced by two parents (or an organism that can self-) The from the gametes of one parent (eg, eggs) are placed on one axis of the Punnett square while alleles from the gametes of the other parent (egsperm) are placed on the other 1. Pea plants have two alleles for height T is the dominant allele and produces tall plants recessive allele and produces short plantsConsider two parental pea plants each have the genot and answer the following questions aWhat type of gametes can a plant with genotype produce? bAssign the maternal gametes to one axis in the Punnett square at right Assign the paternal gametes to one axis in the Punnett square at night Copyright 2017 Pearson Educationa. 1 dominant allele will contribute 120/10 = 12 cm to the base height of the plant.b. The height of the parent plant 1 Genotype of the parent plant 1 – D1D1D2D2D3D3d4d4d5d5 The height of the parent plant 2 Genotype of the parent plant 2 – d1d1d2d2d3d3D4D4D5D5Contributing alleles – D4D4D5D5. The height of the plant without any contributing alleles would be 80 cm. The plant with genotype d1d1d2d2d3d3D4D4D5D5 has 4 contributing allele each of which contributes 12 cm to the base. Hence, the height of the plant with genotype d1d1d2d2d3d3D4D4D5D5 would be 80 + 12 + 12 + 12 + 12 = 128 cm. c. Parents – D1D1D2D2D3D3d4d4d5d5 × d1d1d2d2d3d3D4D4D5D5 Gametes – D1D2D3d4d5 × d1d2d3D4D5 F1 generation – D1d1D2d2D3d3D4d4D5d5 The height of the plants of F1 generation = 80 + 12 + 12 + 12 + 12 + 12 = 140 cm Hence, Genotype of the F1 = D1d1D2d2D3d3D4d4D5d5 Phenotype of…
- Phenotypic ratio Type A : Type O = 2:2 or 1:1 Let's Try This! I1. Solve for the genetic problems below. One point each for: a. genotype of the parents b. Punnett square C. genotypic ratio d. phenotypic ratio e. type of Mendelian or non-Mendelian principle. The genotype r/r ; p/p gives fowl a single comb, R/− ; P/−gives a walnut comb, r/r ; P/− gives a pea comb, andR/− ; p/p gives a rose comb (see the illustrations).Assume independent assortment.Single Walnut Pea Rosea. What comb types will appear in the F1 and in the F2and in what proportions if single-combed birds arecrossed with birds of a true-breeding walnut strain?b. What are the genotypes of the parents in a walnut ×rose mating from which the progeny are 38 rose, 38 walnut,18 pea, and 18 single?c. What are the genotypes of the parents in a walnut ×rose mating from which all the progeny are walnut?d. How many genotypes produce a walnut phenotype?Write them outtype P = n! (p)* (q)"* х! (n - х)! Practice Problem: You cross a true-breeding pea plant with red flowers to a true-breeding pea plant with white flowers. All of your offspring have red flowers. Which gene is dominant? Why? What is the genotype of your offspring? You then cross the offspring to each other. What ratio do you expect? Why? You count 1000 plants and look at their flowers. Your results are as follows: 740 red 260 white Does this follow a simple Mendelian inheritance pattern? Why or why not? DADT 2 MEA SUDI ND D LUT IONS
- I U ... B Work through the Punnett square problems completely on a separate sheet of paper. Take a picture of them and attach it to this form to return the assignment. 1. Mendel studied the colors of flowers in his experiments with pea plants. Purple is dominant over white. Let P stand for purple and p stand for white. Make a Punnett square for a cross between two heterozygous purple plants (Pp) and determine all of the probabilities of all phenotypes and genotypes. Page 1 of 1 234 words English (U.S.) Text Predictions: On 100% + Give Feedback to Micro search DELL F3 F4 F5 F6 F7 F8 F9 F10 F12 Home 近An a cross between two true-breeding plants, Parent #1 with yellow, round peas and Parent #2 with green, wrinkled peas, 1. a. What is the genotype of each plant in the cross. What proportion of the F1 progeny will have the same phenotype as Parent #2. After you self the F1s, what proportion of the progeny will have the same phenotype as Parent #1. C. What proportion of the progeny will have the same genotype as Parent # 1. d. b.Using your calculated expected numbers and the following observed numbers for each progeny phenotype, calculate chi-square: 320 short, black, rough hairs 80 long, black, rough hairs Transform the calculated fraction for each phenotype into a number to 2 decimal places, then add and type answer AS NUMBER rounded to one decimal place. 7 2 3 4 % 5 MacBook Pro 6 7 8