Find the particular solution of the differential equation with the initial condition given below. dy/dx = 3 - 2x2 ;y = - 2 when x = 0 %3D Оа. у- Зx- (2/3)х3 + 2 O b. y = 3x - (2/3)x³ - 4 Ос. у- 3x- (2/3)х3 +4 O d. y = 3x - (2/3)x³ - 2

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