Find upper and lower bounds for the leading eigenvalue of the regular Sturm-Liouville problem "-x²+= 0, 0 < x < 1, φ" φ λφ 20(0) — '(0) = 0, o'(1) = 0.

Show that A=[0110] has no real eigenvalues.

Find the eigenvalue and eigenfunctuons of the Sturm-Liouville problems:  (xy')'+(lamda/x)y=0, y(1)=y(e^2)=0

x'(t) = of the any - 2 5-6 4 1-4-6|x (t) x (0) = -2 + -3 1 The only eigen value of this matrix is -3, a triple root. You must explicitly find matrix involved, with the exception cannot involve Also, your answer 0 imaginary any matrix inverses. number i.