Fix the following code: left = 10 right = 20 while left <= right: print(left) left = left + 2 If the code runs without error, how many numbers are there? Add your answer
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- Question 8 Fix the following code: left = 10 right = 20 while left <= right: print(left) left = left + 2 If the code runs without error, how many numbers are there? Add your answere11: Find the value of A for the following: A = (5 + 2* 3+ (( 3-2)* 7)+ -9) /2.Write a code to find prime numbers between 100 and 200 Write a code which find power of number from 1 to n Example 2 raise to power 0 = 1 2 raise to power 1 = 2 2 raise to power 2 = 4 2 raise to power 3 = 8 2 raise to power 4 = 16 2 raise to power 5 = 32
- Reza Enterprises sells tickets for buses, tours, and other travel services. Because Reza frequently mistypes long ticket numbers, Reza Enterprises has asked his students to write an application that shows if a ticket is invalid. Your application/program tellsthe ticket agent to enter a six-digit ticket number. Ticket numbers are designed so that if you lose the last digit of the number, then divide by 7, the remainder of the division is exactly the same to the last dropped digit. This process is shown below: Step 1: Enter the ticket number; for example 123454 Step 2: Remove the last digit, leaving 12345 Step 3: Determine the remainder when the ticket number from step 2 is divided by 7. In this case, 12345 divided by 7 leaves a remainder of 4. Step 4: Display a message to the ticket agent indicating whether the ticket number is valid or not.. Test your application with the following ticket numbers: - 123454; is a valid ticket number - 147103; is a valid ticket number -…Print "user_num1 is negative." if user_num1 is less than 0. End with newline. Assign user_num2 with 1 if user_num2 is greater than 12. Otherwise, print "user_num2 is less than or equal to 12.". End with newline. My code: user_num1 = int(input())user_num2 = int(input()) if user_num1 < 0: print("user_num1 is negative.") if user_num2 > 12: user_num2 == 1 else: print("user_num2 is less than or equal to 12.") print('user_num2 is', user_num2) When the input is 0 and 13 my output for user_num2 is 13 and it should be 1. I don't know what I'm doing wrong.Please fix the code see picture for error. Thank you
- Credit Card Number CheckThe last digit of a credit card number is the check digitwhich protects against transcription errors such as an error in a single digit or switching two digits. The following method is used to verify actual credit card numbers but, for simplicity, we will describe it for numbers with 8 digits instead of 16: Starting from the rightmost digit, form the sum of every other digit. For example, if the credit card number is 4358 9795, then you form the sum 5 + 7 + 8 + 3 = 23 . Double each of the digits that were not included in the preceding step. Add all digits of the resulting numbers . For example, with the number given above, doubling the digits. starting with the next-to-last one, yields 18 18 10 8. Adding all digits in these values yields 1 + 8 + 1 + 8 + 1 + 0 + 8 = 27 Add the sums of the two preceding steps . If the last digit of the result is 0, the number is valid . In our case , 23 + 27 = 50 , so the number is valid . Write a program that implements this…Magic program ask user to enter three integers by the user, the three integers represent left bound,right bound and arbitrary digit ‘m’, where left bound is less than right bound. Program should print allmagic numbers in the given range that doesn’t contain digit 'm'. The number is magic if its every digit islarger than the sum of digits which are on the right side of that digit. For example, 94210 is magicnumber because 1 > 0, 2 > 1+0, 4>2+1+0, and 9 > 4+2+1+0.Write a complete C program that Call only One Function (magic_numbers) that will print all magicnumbers excluding a given digit ‘m’ that also entered by user ?Fix the following code: scores = 1 while scores < 20: scores = scores + 2 print(scores) Once the code is running without error, what is the resulting value? Note: If you obtained a list of values, just input in the test the highest value
- # given a radius, find the area of a circle # use value of pi as 3.1415 def get_area_circle(r): """ what it takes radius of a circle (any positive real number) what it does: computes the area of a circle given a radius, find the area of a circle area = pi*r2 (pi times r squared) what it returns area of a circle. Any positive real number (float) """ # your code goes in hereCredit Card Number Check. The last digit of a credit card number is the check digit, which protects against transcription errors such as an error in a single digit or switching two digits. The following method is used to verify actual credit card numbers but, for simplicity, we will describe it for numbers with 8 digits instead of 16:• Starting from the rightmost digit, form the sum of every other digit. For example, if thecredit card number is 4358 9795, then you form the sum 5 + 7 + 8 + 3 = 23.• Double each of the digits that were not included in the preceding step. Add all digits ofthe resulting numbers. For example, with the number given above, doubling the digits,starting with the next-to-last one, yields 18 18 10 8. Adding all digits in these valuesyields 1 + 8 + 1 + 8 + 1 + 0 + 8 = 27.• Add the sums of the two preceding steps. If the last digit of the result is 0, the number isvalid. In our case, 23 + 27 = 50, so the number is valid.Write a program that implements this…Credit Card Number Check. The last digit of a credit card number is the check digit, which protects against transcription errors such as an error in a single digit or switching two digits. The following method is used to verify actual credit card numbers but, for simplicity, we will describe it for numbers with 8 digits instead of 16:• Starting from the rightmost digit, form the sum of every other digit. For example, if thecredit card number is 4358 9795, then you form the sum 5 + 7 + 8 + 3 = 23.• Double each of the digits that were not included in the preceding step. Add all digits ofthe resulting numbers. For example, with the number given above, doubling the digits,starting with the next-to-last one, yields 18 18 10 8. Adding all digits in these valuesyields 1 + 8 + 1 + 8 + 1 + 0 + 8 = 27.• Add the sums of the two preceding steps. If the last digit of the result is 0, the number isvalid. In our case, 23 + 27 = 50, so the number is valid.Write a program that implements this…
