Following are the results of a field dry unit weight determination test on a compacted soil by using the sand cone method with a custom-made, non-conventional sand-cone device: · . ● . . . (A) Calibrated dry density of Ottawa sand - 1667 kg/m³ Calibrated mass of Ottawa sand to fill the cone - 0.117 kg Mass of jar + cone + sand (before use) - 5.99 kg Mass of jar + cone + sand (after use) - 2.81 kg Mass of moist soil removed from hole - 3.331 kg Moisture content of moist soil - 11.6% Determine the dry unit weight of compaction in the field. (Show all pertinent volume-weight relationships and calculations.) (B) If the relative compaction in the field is reported to be 95.8%, what was the maximum dry unit weight of compaction obtained in the laboratory? (Show all pertinent volume-weight relationships and calculations.)

Following are the results of a field dry unit weight determination test on a compacted soil by using the sand cone method with a custom-made, non-conventional sand-cone device: · . ● . . . (A) Calibrated dry density of Ottawa sand - 1667 kg/m³ Calibrated mass of Ottawa sand to fill the cone - 0.117 kg Mass of jar + cone + sand (before use) - 5.99 kg Mass of jar + cone + sand (after use) - 2.81 kg Mass of moist soil removed from hole - 3.331 kg Moisture content of moist soil - 11.6% Determine the dry unit weight of compaction in the field. (Show all pertinent volume-weight relationships and calculations.) (B) If the relative compaction in the field is reported to be 95.8%, what was the maximum dry unit weight of compaction obtained in the laboratory? (Show all pertinent volume-weight relationships and calculations.)

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Following are the results of a field unit weight determination test performed bymeans of the sand cone method:• Calibrated dry density of Ottawa sand = 104 lb/ft3• Mass of Ottawa sand to fill the cone = 0.258 lb• Mass of jar + cone + sand (before use) = 13.21 lb• Mass of jar + cone + sand (after use) = 6.2 lb• Mass of moist soil from hole = 7.3 lb• Moisture content of moist soil = 11.6%Determine: Dry unit weight of compaction in the field.
4.2 For a field test the technician is using a sand with a density of 96.7 pcf in his sand cone test. Calculate the dry density, degree of saturation and moisture content of a compacted fill using the following data that the technician collected: Weight of sand cone bottle before test (full of sand): Final weight of sand cone (some sand remains): Weight of sand needed to fill cone: Weight of fill soil excavated from hole + bucket: Weight of bucket used to collect fill soil: 15.14 Ibs 3.97 Ibs 2.67 Ibs 12.37 Ibs 0.76 Ibs Moisture content of fill soil: Empty can: 48.1 g Can + moist soil: 253.7 g Can + dry soil: 237.1 g
Following are the results of a field unit-weight determination test performed on the same soil by means of the sand cone method: -Calibrated dry unit weight of Ottawa sand = 15.4019 kn/m3 -Calibrated weight of Ottawa sand to fill the cone = 5.3496 N -Weightof jar + cone + sand (before use) = 74.451 N -Weightof jar + cone + sand (after use) = 46.886 N -Weight of moist soil from hole = 29.509 N -Moisture content of moist soil = 10.21% DETERMINE AND SHOW COMPLETE SOLUTION 1. Dry density of compaction in the field in kg/cu.m.
As part of a quality controlprogram, the field inspection engineer conducted a sand cone test to determine the field density. The following data were recorded using the sand cone method. • Calibrated dry density of Ottawa sand = 1667 ??/?3• Mass of Ottawa sand to fill the cone = 0.117 kg• Mass of jar + cone + sand (before use) = 6.1 kg• Mass of jar + cone + sand (after use) = 2.83 kg• Mass of moist soil from hole = 3.35 kg• Moisture content of moist soil = 16.1%a. Determine the dry unit weight of compaction in the field. (ANS: 14.97kn/m3) PLS ANSWER NUMBER 2 WITH COMPLETE SOLUTION 2. What is the relative compaction in the field if the maximum dry unit weight in the laboratory is 15.93 ??/?3?
Following are the results of a filed unit weight determination test on soil with the sand cone method: Calibrated dry density of Ottawa Sand = 1667kg/m³ Calibrated mass of Ottawa sand to fill the cone =0.177kg Mass of jar + cone + sand (before use) = 5.99kg Mass of jar + cone + sand (after use) = 2.81kg Mass of soil from hole = 3.331kg Moisture content of moist soil = 11.6% 38. Determine the dry unit weight of soil in the field. (kN/m³) с. 17.78 а. 18.56 b. 20.45 d. 16.25 39. If the maximum dry unit weight of the soil is, 17.54KN/m³, calculate the relative compaction. a. 92.67% b. 86.52% С. 88.97% d. 95.45%
Following are the results of a filed unit weight determination test on soil with the sand cone method: Calibrated dry density of Ottawa Sand = 1667kg/m³ Calibrated mass of Ottawa sand to fill the cone =0.177kg Mass of jar + cone + sand (before use) = 5.99kg Mass of jar + cone + sand (after use) = 2.81kg Mass of soil from hole = 3.331kg Moisture content of moist soil = 11.6% 38. Determine the dry unit weight of soil in the field. (kN/m³) с. 17.78 а. 18.56 b. 20.45 d. 16.25 39. If the maximum dry unit weight of the soil is, 17.54KN/m³, calculate the relative compaction. 92.67% b. 86.52% c. 88.97% d. 95.45% a.
A liquid limit test on a clay was performed with the following results. The natural water content of the clay is 38% and plastic limit is 21%. Number of Blows 6 12 20 28 32 Water content (%) 52.5 47.1 42.3 38.6 37.5 What is the liquidity index of this clay? (Use Interpolation) Group of answer choices 0.895 0.96 1.08 0.90 Please answer this asap. For upvote. Thanks
Maximum and minimum void ratios of a sand sample were determined in the laboratory to be 0.9 and 0.3, respectively. If the void ratio of another sample of the same sand is found to be 0.53, calculate the relative density of the second sand sample. (Type your answer as a percentage %)
Q3. A 1200 g sample of Gravel in the SSD condition in air and weighed 770 g when immersed in water. Also, a 500 g sample of Sand in the SSD condition in air and weighed 300 g when immersed in water Calculate the BSG(SSD) of the sand and gravel 1) the BSG (SSD) of the Gravel * 1.2.791 2.4.71 3.3.703 4.2.50 2) the BSG (SSD) of the Sand * 1.2.221 2.3.590 3.2.500 4.3.232 Choose one answer and write the answer number for me
3. In a sieve analysis of a given sample of sand the following data were obtained. Effective grain size = 0.25 mm, uniformity coefficient 6.0, coefficient of curvature = 1.0. Sketch the curve on semilog paper.
A 627-g sample of sand was found to have the following amounts of material retained on each sieve/pan: 3/8 in. = 22 g, No. 4 = 45 g, No. 8 = 96 g, No. 16 = 122 g, No. 30 = 163 g. No. 50 86 g, No. 100 = 51 g, No. 200 = 30 g, pan = 11 g a. Calculate the fineness modulus of the sand. b. Is this sieve analysis valid for acceptance purposes? Explain why. c. Does the sand meet the particle size criteria of ASTM C 33. Fully justify your answer (list and check all relevant criteria from ASTM C33)
An ASTM D 854 test was done on a sand. The data are shown below. Calculate the specific gravity. Mass of pychnometer = 46.1 grams Mass of pychnometer and dry soil = 67.4 grams Mass of pychnometer, dry soil and water = 157.7 grams Mass of pychnometer and water = 140.9 grams