For NH4Cl and NaCH3COO, perform the following calculations: 1. Calculate [H3O+] using the equation below and the given pH values in Table 7b-1. 2. Calculate [OH-] using any of the equations below. [H3O+][OH-] = Kw = 1.00 × 10-14 OR pOH = 14 – pH [OH-] = 10-pOH 3. Construct an ICE table for the hydrolysable ion. 4. Calculate Kh using the equations below, whichever is applicable. If the ion is a conjugate acid of a weak base, then Kh = Ka. If the ion is a conjugate base of a weak acid, then Kh = Kb. Ka = weak base H3O+[cation or conjugate acid] 5. Calculate Ki using the given equation. If Kh = Ka, then Ki = Kb. If Kh = Kb, then Ki = Ka.

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For NH4Cl and NaCH3COO, perform the following calculations:

1. Calculate [H3O+] using the equation below and the given pH values in Table 7b-1.

2. Calculate [OH-] using any of the equations below.
[H3O+][OH-] = Kw = 1.00 × 10-14 OR
pOH = 14 – pH
[OH-] = 10-pOH

3. Construct an ICE table for the hydrolysable ion.
4. Calculate Kh using the equations below, whichever is applicable.
If the ion is a conjugate acid of a weak base, then Kh = Ka.
If the ion is a conjugate base of a weak acid, then Kh = Kb.
Ka = weak base H3O+[cation or conjugate acid]
5. Calculate Ki using the given equation.
If Kh = Ka, then Ki = Kb.
If Kh = Kb, then Ki = Ka.
KiKh = Kw

Table 7b-1. pH of different salt samples.
Parameter
dH₂O
dH₂O
NaCl
(boiled)
(unboiled)
pH
6.86
6.30
7.92
Samples
NHẠCI
4.72
NaCH3COO
9.31
(NH4)₂CO3
8.55
Transcribed Image Text:Table 7b-1. pH of different salt samples. Parameter dH₂O dH₂O NaCl (boiled) (unboiled) pH 6.86 6.30 7.92 Samples NHẠCI 4.72 NaCH3COO 9.31 (NH4)₂CO3 8.55
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For NH4Cl and NaCH3COO, perform the following calculations:

1. Calculate [H3O+] using the equation below and the given pH values in Table 7b-1.

2. Calculate [OH-] using any of the equations below.
[H3O+][OH-] = Kw = 1.00 × 10-14 OR
pOH = 14 – pH
[OH-] = 10-pOH

3. Construct an ICE table for the hydrolysable ion.
4. Calculate Kh using the equations below, whichever is applicable.
If the ion is a conjugate acid of a weak base, then Kh = Ka.
If the ion is a conjugate base of a weak acid, then Kh = Kb.
Ka = weak base H3O+[cation or conjugate acid]
5. Calculate Ki using the given equation.
If Kh = Ka, then Ki = Kb.
If Kh = Kb, then Ki = Ka.
KiKh = Kw

 

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