For the network in Fig. 3.6, establish a measurement model considering:(a) PI2 and P I 3 as state variables; (b) PI and P3 as state variables. Compare the results with those obtained for Example 3.6. Discuss the pros and cons of each of the three choices of state variables.The conclusion of Example 3.6 is given in the attached picture. I need the total solution of this question. Detailed answer is needed. 12X12 = .02 p.u.P2x13 = .01 p.u.223 =.01 p.u.P1P3MeterFigure 3.6. Three-bus system. Example 3.6:Consider the three-bus system shown in Fig. 3.6. The problem variables, thenetwork model equations, and the state variables are the same as in Example3.3.2212 = .02 p.u.P2*13 = .01 p.u.I23 = .01 p.u.P13MeterFigure 3.6.Three-bus system.Measurement model: In this case there are four measurements (Pmeas, Pmeas,Pgmeas, and Peas) which are expressed in terms of the state variables (62and 03):-50 62 – 100 03Pineas150 02 – 100 63 =omeas-100 02 + 200 03 = Pmeas-100 03 = PmeasThese equations can be rewritten in matrix form as follows-50 -100PmeasPmeasPmeas150 -100-1002000 -100.pmeas13where the Jacobian matrix, H, the state variable vector, x, and the mea-surement vector z are as follows-50 -100150 -100-- -)Pmeas(2)PmeasPmeasH =X =03z =-100200-100Pmeas13

In given network let θ1=0 ..referance voltage angle there are 8 variables P1, P2, P3, P12, P23,…

For the network in Fig. 3.6, establish a measurement model considering: (a) PI2 and P I 3 as state variables; (b) PI and P3 as state variables. Compare the results with those obtained for Example 3.6. Discuss the pros and cons of each of the three choices of state variables. The conclusion of Example 3.6 is given in the attached picture. I need the total solution of this question. Detailed answer is needed.

For the network in Fig. 3.6, establish a measurement model considering: (a) PI2 and P I 3 as state variables; (b) PI and P3 as state variables. Compare the results with those obtained for Example 3.6. Discuss the pros and cons of each of the three choices of state variables. The conclusion of Example 3.6 is given in the attached picture. I need the total solution of this question. Detailed answer is needed.

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter2: Fundamentals

Section: Chapter Questions

Problem 2.36P

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A DC Optimal Power Flow problem is to be solved for a 3-bus network. The per-unit reactances of the lines interconnecting the buses are as follows: X12 = 0.1pu, X13 = 0.12 pu and X23 = 0.2 pu. There is a generator at each bus. The loads at buses 1, 2 and 3 are 150MW, 200mw, and 100MWrespectively. Bus 1 is taken as the reference bus, and SBase = 100 MVA. Which one of the below is a constraint of the DCOPF problem? Select one: O a. None of these O b. -500 0₂-1000 03 = P3 - 110 O c. 1500 0₂-500 03 = P₂ - 220 O d. 1500 0₂-500 03 = P₂ - 200 O e. -500 0₂-1000 03 = P3 - 150 O f. -1500 8₁-1000 03 = P₁ - 150
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b) A fault occurs at bus 4 of the network shown in Figure Q3. Pre-fault nodal voltages throughout the network are of 1 p.u. and the impedance of the electric arc is neglected. Sequence impedance parameters of the generator, transmission lines, and transformer are given in Figure Q3, where X and Y are the last two digits of your student number. V₁ = 120° p.u. V₂ = 120° p.u. jX(1) j0.1Y p.u. jX2)= j0.1Y p.u. jXko) j0.1X p.u. - 0 jX(1) = j0.2 p.u. 1JX(2) = 0.2 p.u. 2 jX1(0) = j0.25 p.u. jX2(1) j0.2 p.u. V₁=1/0° p.u. jX(2(2) = j0.2Y p.u. jX2(0) = j0.3X p.u. = V₂ = 120° p.u. jXT(1) j0.1X p.u. jXT(2) j0.1X p.u. JX3(1) j0.1Y p.u. JX3(2)=j0.1Y p.u. jXT(0) j0.1X p.u. JX3(0)=j0.15 p.u. 0- = 3 = Figure Q3. Circuit for problem 3b). For example, if your student number is c1700123, then: jXa(n) = j0.13 p. u., jXa(z) = j0.13 p. u., and jXa(o) = j0.12 p. u. 4 (i) Assuming a balanced excitation, draw the positive, negative and zero sequence Thévenin equivalent circuits as seen from bus 4. (ii)…
A DC Optimal Power Flow problem is to be solved for a 3-bus network. The per-unit reactances of the lines interconnecting the buses are as follows: X12 = 0.25 pu, X13 = 0.15 pu and X23 = 0.2 pu. There is a generator at each bus. The loads at buses 1, 2 and 3 are 125 MW, 300 MW and 100 MW respectively. Bus 1 is taken as the reference bus, and SBase = 100 MVA. Which one of the below is NOT a constraint of the DCOPF problem? Select one: O a. -400 02 - 666.67 03 = P, - 125 O b. None of these C. -500 02 - 1166.67 03 = P3 - 100 d. 900 02 - 500 03 = P2 - 300
Which of the following cannot be determined with the help of load flow analysis?a) frequency of busbar voltagesb) active and reactive forcesc) phase angle of busbar voltagesd) loss of strengthe) amplitude of busbar voltages
b) A fault occurs at bus 3 of the network shown in Figure Q4. Pre-fault nodal voltages throughout the network are of 1 p.u. and the impedance of the electric arc is neglected. Sequence impedance parameters of the generator, transmission lines, transformer and load are given in Figure Q4. V₁ = 120° p.u. V₂ = 120° p.u. V₂ = 1/0° p.u. V₂= 120° p.u. jXj0.1 p.u. JX2) 0.1 p.u. jX0j0.15 p.u. jXn-j0.2 p.u. 1 JX(2)-j0.2 p.u. 2 jX)=j0.25 p.u. JX20-10.15 p.u. jXa(z)-j0.2 p.u. 4 jX2(0)=j0.2 p.u. jXT(1) j0.1 p.u. jXT(2)=j0.15 p.u. jXT(0)=j0.1 p.u. Figure Q4. Circuit for problem 4b). = jXj0.1 p.u. j0.1 p.u. - JX(2) JXL(0) 10.1 p.u. = (i) Assuming a balanced excitation, draw the positive, negative and zero sequence Thévenin equivalent circuits as seen from bus 3. (ii) Determine the positive sequence fault current for the case when a three- phase-to-ground fault occurs at bus 3 of the network. (iii) Determine the short-circuit fault current for the case when a one-phase- to-ground fault occurs at bus…
sketch and express in terms of unit step and ramp functions
What happens if a new pi equivalent circuit given the busbar admintas matrix and reactance and susceptance values given in the figure between busbars 1 and 3 in a 3 bus power system is connected.
For a system consist from 3 buses and bus 1 is the slack bus. The data of the system are:- -0.2 -0.05 Ybus-j-0.2 0.225 -0.025 p.u. -0.05 -0.025 0.075 V₁=1+j0 p.u., P₂+jQ=0.6+j0.25 p.u., P3+jQ3-0.8+j0.5 p.u. 0.25 By using Gauss-Siedal method, the voltage of the bus 2 after two iteration is -0.762-j0.826 -0.762+j0.826 0.762+j0.826 0.762-j0.826 By using Gauss-Siedal method, the voltage of the bus 1 after two iteration is 1+j0 0+j1 -0.3-j0.6 0.3-j0.6
Bus bar system which ensures continuity of supply during maintanence is ............ O duplicate bus bar O single bus bar without sectionalization O single bus bar O single bus bar with sectionalization
b) A fault occurs at bus 4 of the network shown in Figure Q3. Pre-fault nodal voltages throughout the network are of 1 p.u. and the impedance of the electric arc is neglected. Sequence impedance parameters of the generator, transmission lines, and transformer are given in Figure Q3, where X and Y are the last two digits of your student number. jX(1) j0.1Y p.u. jX2)= j0.1Y p.u. jXko) = j0.1X p.u. V₁ = 120° p.u. V₂ = 120° p.u. (i) (ii) 0 jX(1) = j0.2 p.u. 1 jx(2) j0.2 p.u. 2 jX1(0) = j0.25 p.u. jXT(1) jXT(2) 종 3 j0.1X p.u. JX3(1) j0.1Y p.u. j0.1X p.u. JX3(2) j0.1Y p.u. jXT(0) j0.1X p.u. JX3(0)=j0.15 p.u. 0 = x = 1, jX2(1) j0.2Y p.u. V₁=1/0° p.u. jX(2(2) = j0.2Y p.u. jX2(0) = j0.3X p.u. = V3 = 120° p.u. Figure Q3. Circuit for problem 3b). For example, if your student number is c1700123, then: y = 7 = = jXa(r) = j0.13 p.u., jXa(z) = j0.13 p. u., and jXa(o) = j0.12 p. u. Assuming a balanced excitation, draw the positive, negative and zero sequence Thévenin equivalent circuits as seen from…
QUESTION-2: In the two-buses, one breaker arrangement shown in the figure left, initially S3, S5, B2, S6, S8, S10, B3 and S11 are closed and the others are open. Make a list of operations required to: a) Take B3 out of service. b) Take Bus 2 out of service. without any service interruption in any feeders. Bus 1 S1 B1 S2 Bus 2 S3 S4 S8 S9 S5 s10 B2 B3 S12 S6 S7 s11