For the reaction NO2(g) + NO(g) N2O(g) + O2(g) K=0.914. Equal amounts of NO and NO2 are to be placed into a 5.00 L container until the N2O concentration at equilibrium is 0.0616 M. How many moles of NO and NO2 must be placed in the container? moles of NO = moles of NO2 = i mol

Chemistry for Engineering Students
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Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 12.45PAE: The following equilibrium is established in a closed container: C(s)+O2(g)CO2(g)H=393kJmol1 How does...
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For the reaction
NO2(g) + NO(g) N2O(g) + O2(g)
K=0.914. Equal amounts of NO and NO2 are to be placed into a 5.00 L container until the N2O concentration at equilibrium
is 0.0616 M.
How many moles of NO and NO2 must be placed in the container?
moles of NO = moles of NO2 = i
mol
Transcribed Image Text:For the reaction NO2(g) + NO(g) N2O(g) + O2(g) K=0.914. Equal amounts of NO and NO2 are to be placed into a 5.00 L container until the N2O concentration at equilibrium is 0.0616 M. How many moles of NO and NO2 must be placed in the container? moles of NO = moles of NO2 = i mol
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