The IR, and 1H NMR spectra of a compound with formula C5H6O2 are shown below. Determine the structure of the compound. You must fill all the parts to this question in the given spaces. FAYSolvent: CDC13D483040002.10Solution of problem # 2:Degree of unsaturation:IR interpretation:30003000Peak A (4.25 ppm)4,0C5H602POOR19832000 Wavenumber 1500cm 13.01.012.5The number underneath each peak in 'H NMR spectrum represents relative integration value.Peak B (2.90 ppm)10001000800500'H NMR interpretation (I want a picture of the fragment that you can determine from the shift andsplitting):Structure of unknown compound3.15Peak C (1.35 ppm)

Given Molecular formula C5H6O2 IR and NMR spectra

FW m Transmittance % Solvent: CDC13 4830 4000 2.10 1000 3000 CsH₂O2 2008 1983 2000 Wavenumber 1500 cm-1 3.0 1.01 2.5 1000 1000 300 500 3.15 The number underneath each peak in 'H NMR spectrum represents relative integration value.

FW m Transmittance % Solvent: CDC13 4830 4000 2.10 1000 3000 CsH₂O2 2008 1983 2000 Wavenumber 1500 cm-1 3.0 1.01 2.5 1000 1000 300 500 3.15 The number underneath each peak in 'H NMR spectrum represents relative integration value.

Organic Chemistry: A Guided Inquiry

2nd Edition

ISBN:9780618974122

Author:Andrei Straumanis

Publisher:Andrei Straumanis

ChapterL4: Proton (1h) Nmr Spectroscopy

Section: Chapter Questions

Problem 15E

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Question

The IR, and 1H NMR spectra of a compound with formula C5H6O2 are shown below. Determine the structure of the compound. You must fill all the parts to this question in the given spaces.

FAY
Solvent: CDC13
D
4830
4000
2.10
Solution of problem # 2:
Degree of unsaturation:
IR interpretation:
3000
3000
Peak A (4.25 ppm)
4,0
C5H602
POOR
1983
2000 Wavenumber 1500
cm 1
3.0
1.01
2.5
The number underneath each peak in 'H NMR spectrum represents relative integration value.
Peak B (2.90 ppm)
1000
1000
800
500
'H NMR interpretation (I want a picture of the fragment that you can determine from the shift and
splitting):
Structure of unknown compound
3.15
Peak C (1.35 ppm)

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