Figure 3 B A uniform rod AB of weight W has its end A freely hinged to a point on a fixed vertical wall. The rod is held in equilibrium, at angle to the horizontal, by a force of magnitude P. The force acts perpendicular to the rod at B and in the same vertical plane as the rod, as shown in Figure 3. The rod is in a vertical plane perpendicular to the wall. The magnitude of the vertical component of the force exerted on the rod by the wall at A is Y. It can be shown that Y = W 2 (2 - cos² 0) Given that = 45°, find the magnitude of the force exerted on the rod by the wall at A, giving your answer in terms of W and in exact form.

Physics for Scientists and Engineers with Modern Physics
10th Edition
ISBN:9781337553292
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter12: Static Equilibrium And Elasticity
Section: Chapter Questions
Problem 31AP: A uniform sign of weight Fg and width 2L hangs from a light, horizontal beam hinged at the wall and...
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Figure 3
B
A uniform rod AB of weight W has its end A freely hinged to a point on a
fixed vertical wall. The rod is held in equilibrium, at angle to the horizontal,
by a force of magnitude P. The force acts perpendicular to the rod at B and
in the same vertical plane as the rod, as shown in Figure 3. The rod is in a
vertical plane perpendicular to the wall. The magnitude of the vertical
component of the force exerted on the rod by the wall at A is Y.
It can be shown that Y
=
W
2
(2 - cos² 0)
Given that = 45°, find the magnitude of the force exerted on the rod by
the wall at A, giving your answer in terms of W and in exact form.
Transcribed Image Text:Figure 3 B A uniform rod AB of weight W has its end A freely hinged to a point on a fixed vertical wall. The rod is held in equilibrium, at angle to the horizontal, by a force of magnitude P. The force acts perpendicular to the rod at B and in the same vertical plane as the rod, as shown in Figure 3. The rod is in a vertical plane perpendicular to the wall. The magnitude of the vertical component of the force exerted on the rod by the wall at A is Y. It can be shown that Y = W 2 (2 - cos² 0) Given that = 45°, find the magnitude of the force exerted on the rod by the wall at A, giving your answer in terms of W and in exact form.
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