Given the data below for the decomposition of peroxyacetyl nitrate, an air pollutant produced in photochemical smog: T, K k, s-1 273.15 5.6 x 10-6 283.15 3.2 x 10-5 293.15 1.6 x 10-4 303.15 7.6 x 10-4 Using linear regression, calculate the: A. Slope [Select] B. y-intercept [Select] C. Collision frequency factor [Select] < > >

Given the data below for the decomposition of peroxyacetyl nitrate, an air pollutant produced in photochemical smog: T, K k, s-1 273.15 5.6 x 10-6 283.15 3.2 x 10-5 293.15 1.6 x 10-4 303.15 7.6 x 10-4 Using linear regression, calculate the: A. Slope [Select] B. y-intercept [Select] C. Collision frequency factor [Select] < > >

Appl Of Ms Excel In Analytical Chemistry

2nd Edition

ISBN:9781285686691

Author:Crouch

Publisher:Crouch

Chapter2: Basic Statistical Analysis With Excel

Section: Chapter Questions

Problem 12P

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For the following data set: 18.3g, 184g 13g 15.0S Determines whether the questionable data is retained or discarded at 95% confidence. Critical Q values a. Reject b. Retain Valores críticos Número de datos 90% 95% 99% 3 0.941 0.970 0.994 0.765 0.829 0.926 0.642 0.710 0.821 5
7 8 VNICH a12 11 VIA COHA CONHOH a. 1.009E-05 C. Construct the Gran plot. What is the value of the slope (to nearest 3 decimal a. 4.061E-04 b. 5.031E-04 20.00 25.00 30.00 40.00 1.000E-05 -1.009E-05 d. -1.099E-05 -1.000E-05 Obtain the value of intercept. a. b. C. 6.281E-03 d. 2.895E-05 e. 3.031E-03 What is the value of R2 ? e. 0.9999 d. 0.9989 0.9996 a. 1.0001 d. 1.0000 Clear my choice 50.00 0.1000 0.1000 pH 4.82 5.00 5.18 5.60 1.099E-05 1.099E-05 What is the value of acid dissociation constant Ka? 1.000E-05 1.009E-05 [H₂O*]V NAOH
Consider the calcination of CaCO3: CaCO3 -> CaQ + CO, Before calcination, the initial weight of CaCO3 is 2.5g. After calcination, the final weight of CaCO3 was measured at 2.0 g. Calculate the conversion of CaCO; particles (x) using the following equation: m CaCO, -m CaCo, ) x = m Caco, -MCao |
(9.29 × 105/8)-20.81 = with correct sig figs
Choices for slope: a. -1.35 x 10^4 b. 1.35 x 10^4 c. -1.09 x 10^4 d. 1.09 x 10^4 choices for y intercept: a. -27.8 b. 27.8 c. 37.4 d. -37.4 choices for pearson: a. -0.962 b. -1000 c. -0.982 activation energy a. 9.06 x 10^4 b. 113 c. 90.65 collision frequency factor A a. 1.15 x 10^12 b. 113 c. 90.65
Com X Bb Mas X Mas X Hom X K! Kahx Exan X K! Kah X Mitc X КI Kah X K Kah x K! Kah x Kah x K Kahx C session.masteringchemistry.com/myct/itemView?assignmentProblemID=134214560 Apps New Tab Effect of Salinity on... Sleep Disorders | M... P Philo American Journal ... Zeeshan JBAS Ic Wait for Next Quest... oramge juice Effect c
THE Y-INTERCEPT FOR THE FOLLOWING GRAPH IS: -35.0 In K# -10749 -27 -35.2 -35.4 -35.6 -35.8 -36.0 -36.2 7.4 In K = -AH/RT+AS*/R In K* = -10,749/T-27 R² = 0.974 7.6 7.8 974 NOT ENOUGH INFORMATION 8.2 8.0 (1/7)/10-4K-1 8.4 8.6
10) The following results were obtained in an analysis of iron content in an ore sample. The results reported as % Fe for each analysis, were as follow: Samples no. 1 3 4 5 6 % Fe 20.10 20.50 18.65 19.25 19.40 19.99 i. Calculate the mean and median from the set of the data above ii. If the true value of %Fe is 19.65 %, calculate the value for absolute error and percentage relative error for sample no. 3 Using Q-test, justify whether an of the data must be rejected at 95 % ii. confidence level iv. Calculate the standard deviation and relative standard deviation of the data.
V. Error Analysis/Questions For the following questions explain what specific error in calculating your Ksp value would occur (i.e. would the Ksp be too HIGH or too LOW), compared to the situation in which no errors occur. When you answer the question, consider how the situation affects the calculation of Ksp. Each answer must have an explanation and type the answer, please. A. The buret was not conditioned (it still had water in it) when you add the HCl. Would the Ksp be too HIGH or too LOW? B. There was Ca(OH)2 solid (that was not filtered off) in your solution to be titrated. Would the Ksp be too HIGH or too LOW? C. You measured 24.00 mL of Ca(OH)2 solution instead of 25.00 mL. Would the Ksp be too HIGH or too LOW? D. The HCl concentration was actually lower than the reported molarity on the bottle. Would the Ksp be too HIGH or too LOW?
1-arr In a study of the gas phase decomposition of phosphine at 120 °C PH3(g)- →1/4 P4(g) + 3/2 H2(g) the concentration of PH3 was followed as a function of time. It was found that a graph of In[PH3] versus time in seconds gave a straight line with a slope of -2.50×10² s1 and a y-intercept of -3.24. Based on this plot, the reaction i v O order in PH, and the half life for the reaction is seconds. zero first second
Sample IdentificationCodeConcentration of M%TA=2-log(%T)Q50004.00 x 10-417.90.75Q50013.20 x 10-425.00.6Q50022.40 x 10-435.70.46Q50031.60 x 10-450.20.3Q50048.000 x 10-570.80.15SampleIdentificationCode%TA=2-log(%T)AMQ0210150143.70.359518560.360.000192Q0210150244.10.355561410.360.00018Q0210150343.80.358525890.360.00017Q0210150444.10.355561410.360.00018Q0210150543.80.358525890.360.00017What was their percent error?43%Does Batch 021015 meet legal requirements?No, because it is not between 2.85 * 10(4) and 3.15 * 10(4)Well #DropsBluedye1234567891012345678910Drops 9Distilled water876543210Concne 0.26tration0.52Test Tube #0.781.041.3Solutions3Concentration (M)2.082.32.6Concentration (ppm)1:1 dilution11.82Starting Dilution21.562:1 dilution0A.Zero standard0Was your calibration curve as linear as you expected?B.Did you experience any â€œdriftâ€ of the resistance readings?C.What is the equation of your best-fit line?D.What commercial drink did you analyze?E.Assuming…
2. As the director of a research laboratory you are paid to decide if there is a significant difference between the mean values of two sets of data obtained by two different scientists, a senior scientist and one recently hired. Use 95% CL. (t at df = 10 is 2.23) Data of Senior Scientist: xmoan = 24.66% with s = 0.06% for n = 5 Data of the New Kid: xmean = 24.55% with s = 0.10% for n = 7