Given the thermochemical equations X₂ + 3 Y₂ → 2XY, AH₁ = -330 kJ X₂ +2Z₂ → 2XZ₂ - AH₂ = -190 kJ 2Y₂+Z₂2Y₂Z AH, = -220 kJ Calculate the change in enthalpy for the reaction. 4XY, +7Z₂ 6Y₂Z +4XZ₂ ΔΗ = 1 kJ

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