Please explain this problem step by step 4.10 (See Fluids in the News article titled "Follow those parti-cles." Section 4.1.) Two photographs of four particles in a flowpast a sphere are superposed as shown in Fig. P4.10. The time in-terval between the photos is Ar = 0.002 s. The locations of theparticles, as determined from the photos, are shown in the table.(a) Determine the fluid velocity for these particles. (b) Plot agraph to compare the results of part (a) with the theoreticalvelocity, which is given by V = Vo(1 + a'x'), where a is thesphere radius and V, is the fluid speed far from the sphere.Particle134xatr=0s (ft)-0.500-0.250-0.140-0.120-0.002sFIGURE P4.10xat/- 0.002s (ft)-0.480-0.232-0.128-0.112X.R-0.1t

Given:-∆t=0.002secTo find:-fluid velocity

graphs four particles in s shown in Fig. P4.10. The Ar 0.002 s. The location the photos, are shown in th city for these particles. (b) s of part (a) with the the + ax), where a is the far from the sphere. xat 0.002s (n)

graphs four particles in s shown in Fig. P4.10. The Ar 0.002 s. The location the photos, are shown in th city for these particles. (b) s of part (a) with the the + ax), where a is the far from the sphere. xat 0.002s (n)

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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