H2.0mA scuba diver training in a pool looks at his instructor as shown in the figure. The angle between theray in the water and the perpendicular to the water is 0: 25°.(a) What angle does the ray from the instructor's face make with the perpendicular to the water atthe point where the ray enters?Angle, : 34.190(b) Find the height, H, of the instructor's head above the water, noting that you will first have tocalculate the angle of incidence. Note the scuba diver perceives the instructor as though theincident ray never refracted.

(b) height, h of the instructor's head above the water. tan(90o−34.19o)=2h2(tan55.81o)=hh=2.94m…

Answered: H 2.0m A scuba diver training in a pool…

College Physics

1st Edition

ISBN:9781938168000

Author:Paul Peter Urone, Roger Hinrichs

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Chapter25: Geometric Optics

Section: Chapter Questions

Problem 10PE: A scuba diver training in a pool looks at his instructor as shown in Figure 25.53. What angle does...

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A scuba diver training in a pool looks at his instructor as shown in Figure 25.53. What angle does the ray from the instructor’s face make with the perpendicular to the water at the point where the ray enters? The angle between the ray in the water and the perpendicular to the water is 25.0°. Figure 25.53 A scuba diver in a pool and his trainer look at each other.
Figure P23.28 shows a curved surface separating a material with index of refraction n1 from a material with index n2. The surface forms an image I of object O. The ray shown in red passes through the surface along a radial line. Its angles of incidence and refraction are both zero, so its direction does not change at the surface. For the ray shown in blue, the direction changes according to n1 sin 1 = n2 sin 2. For paraxial rays, we assume 1 and 2 are small, so we may write n1 tan 1 n2 tan 2. The magnification is defined as M = h/h. Prove that the magnification is given by M = n1q/n2p. Figure P23.28
(a) Using information in Figure 25.53, find the height of the instructor's head above the water, noting that you will first have to calculate the angle of incidence. (b) Find the apparent depth of the diver’s head below water as seen by the instructor.
A ray of light strikes a flat, 2.00-cm-thick block of glass (n = 1.50) at ail angle of 30.0 with respect to the normal (Fig. P22.18). (a) Find the angle of refraction at the lop surface. (b) Find the angle of incidence at the bottom surface and the refracted angle. (c) Find the lateral distance d by which the light beam is shifted. (d) Calculate the speed of light in the glass and (e) the time required for the light to pass through the glass block. (f) Is the travel time through the block affected by the angle of incidence? Explain.
A water fountain is at the center of a circular pool as shown in Figure P1.59. A student walks around the pool and measures its circumference C. Next, he stands at the edge of the pool and uses a protractor to measure the angle of elevation of his sightline to the top of the water jet. How high is the fountain?
Electric room heaters use a concave mirror to reflect infrared (IR) radiation from hot coils. Note that IR radiation follows the same law of reflection as visible light. Given that the mirror has a radius of curvature of 50.0 cm and produces an image of the coils 3.00 m away from the mirror, where are the coils?
The disk of the Sun subtends an angle of 0.533 at the Earth. What are (a) the position and (b) the diameter of the solar image formed by a concave spherical mirror with a radius of curvature of magnitude 3.00 m?
An underwater scuba diver sees the Sun at an apparent angle of 45.0 above the horizontal. What is the actual elevation angle of the Sun above the horizontal?
A man shines a flashlight from a boat into the water, illuminating a rock as in Figure P22.21. What is the angle of incidence 1?
Figure P23.28 shows a curved surface separating a material with index of refraction n1 from a material with index n2. The surface forms an image I of object O. The ray shown in red passes through the surface along a radial line. Its angles of incidence and refraction are both zero, so its direction does not change at the surface. For the ray shown in blue, the direction changes according to n1 sin 1 = n2 sin 2. For paraxial rays, we assume 1 and 2 are small, so we may write n1 tan 1 n2 tan 2. The magnification is defined as M = h/h. Prove that the magnification is given by M = n1q/n2p. Figure P23.28
A ray of light, emitted beneath the surface of an unknown liquid with air above it, undergoes total internal reflection as shown in Figure 25.55. What is the index of retraction for the liquid and its likely identification? Figure 25.55 A tight ray inside a liquid strikes the surface at the critical angle and undergoes total internal reflection.
In what substance in Table 1.1 is the speed of light 2.290108 m/s?

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