How do I find the moles excess HCl titrated and Moles HCl absorbed by Tablet Part IV. Determine the percentage of CaCO3 in an antacid tablet.HCl (aq) + NaOH (aq) → NaCl (aq) + H₂0 (1)MolarityDMass of Antacid TabletVolume 3.00M HCl UsedTotal moles HCl added to flaskFinal burette readingInitial burette readingVolume of NaOH usedMolarity of NaOH (from Part II)Moles NaOH usedMoles excess HCl titratedMoles HCl absorbed by Tablet(Hint: It is NOT moles titrated.)Moles CaCO3 in TabletMass CaCO3 in TabletMalys- of sauteIL of CaCO3 in TabletAverage % CaCO3 in Tablet1000m2= 0.0100 5 C4.6293 *10*²=mol ofSolute0.014050.001352917Trial 11.4604 12341s5.00m5,0041,05m41,05m9.6293 x 101.353x10-3>Trial 2L41.05mShow your calculations for "Mass % CaCO3 in Tablet" for at least 1 trail below.105m41108ML55.350.0155.349.629 31 105.329x10-³Tria! 3Z1.234/48.0138.4mc१.८ ।45.75

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How do I find the moles excess HCl titrated and Moles HCl absorbed by Tablet

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter13: The Chemistry Of Solutes And Solutions

Section: Chapter Questions

Problem 137QRT

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Question

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How do I find the moles excess HCl titrated and Moles HCl absorbed by Tablet

Part IV. Determine the percentage of CaCO3 in an antacid tablet.
HCl (aq) + NaOH (aq) → NaCl (aq) + H₂0 (1)
Molarity
D
Mass of Antacid Tablet
Volume 3.00M HCl Used
Total moles HCl added to flask
Final burette reading
Initial burette reading
Volume of NaOH used
Molarity of NaOH (from Part II)
Moles NaOH used
Moles excess HCl titrated
Moles HCl absorbed by Tablet
(Hint: It is NOT moles titrated.)
Moles CaCO3 in Tablet
Mass CaCO3 in Tablet
Malys
- of saute
IL of CaCO3 in Tablet
Average % CaCO3 in Tablet
1000m2
= 0.0100 5 C
4.6293 *10*²=
mol of
Solute
0.01405
0.001352917
Trial 1
1.4604 12341s
5.00m
5,00
41,05m
41,05m
9.6293 x 10
1.353x10-3
>
Trial 2
L
41.05m
Show your calculations for "Mass % CaCO3 in Tablet" for at least 1 trail below.
105m41108
ML
55.35
0.01
55.34
9.629 31 10
5.329x10-³
Tria! 3
Z
1.234/
48.01
38.4mc
१.८ ।
45.75

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