Hydrazine and 1,1-dimethylhydrazine both react spontaneously with Oz and can be used as rocket fuels. N3H4() + O2(g) → N2(g) + 2 H2O(g) N,Hạ (CH,)2() +4 0:(8) + 2 CO: (8) + 4 Hạ0(g) + N2(8) The molar enthalpy of formation of N3H,(() is +50.6 kl mol, and that of N3H2 (CH,)2(0) is +48.9 kJ mol. Use these values, with other A,H values in the table below. Compound A H (kJ/mol) H,O(g) CO(8) -241.83 -393.509 Calculate the specific heat of the reaction hydrazine with oxygen. A,H = -16.7 V kig hydrazine Correct To calculate molar enthalpy of the reaction, the sum of molar standard enthalpies of formation of reactants should be subtracted from molar standard enthalpies of formation of products: A,H" (kJ/mol) = 2 mol x (-241.83 kJ/mol) – 1 mol x x 50.6 kJ/mol = -534.3 kJ/mol Convert the value from (kJ mol) to (kJg): 1 mol (N,H4) 32.05 g (N,H,) A,H" (kJ/g) = -534.3 kJ/mol x = -16.67 kJ/g Calculate specific heat of the reaction 1,1-dimethyikydrazine with onygen. A,H' = 30.06 v kig 1,1-dimethyilhydrazine Correct To calculate molar enthalpy of the reaction, the sum of molar standard enthalpies of formation of reactants should be subtracted from molar standard enthalpies of formation of products: A,H" (kJ/mol) = 2 mol x (-393.509 kJ/mol) + 4 mol x x (-241.83 kJ/mol) – 1 mol x 48.9 kJ/mol --1803.2 kJ/mol Convert the value from (kJ mol) to (kg): 1 mol (N3 H3 (CH3)2) 60.10 g (N;H2 (CH,)2) -30.00 kJ/g A,H" (kJ/g) = -1803.2 kJ/mol x Decide whether the reaction of hydrazine or 1,1-dimethyihydrazine with oxygen provides more energy per gram. O Hydrazine gives more heat per gram when reacting with oxygen. O1,1-Dimethylhydrazine gives more heat per gram when reacting with oxygen. O The compounds give almost the same heat per gram when reacting with oxygen.

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*please answer question C 

the other answer is needed to answer c

 

c

Decide whether the reaction of hydrazine or 1,1-dimethylhydrazine with oxygen provides more energy per gram.

a)Hydrazine gives more heat per gram when reacting with oxygen.

b)1,1-Dimethylhydrazine gives more heat per gram when reacting with oxygen.

c)The compounds give almost the same heat per gram when reacting with oxygen.

 
Hydrazine and 1,1-dimethylhydrazine both react spontaneously with Oz and can be used as rocket fuels.
N3H4() + O2(g) → N2(g) + 2 H2O(g)
N,Hạ (CH,)2() +4 0:(8) + 2 CO: (8) + 4 Hạ0(g) + N2(8)
The molar enthalpy of formation of N3H,(() is +50.6 kl mol, and that of N3H2 (CH,)2(0) is +48.9 kJ mol. Use these values, with other A,H values in the table below.
Compound A H (kJ/mol)
H,O(g)
CO(8)
-241.83
-393.509
Calculate the specific heat of the reaction hydrazine with oxygen.
A,H = -16.7
V kig hydrazine
Correct
To calculate molar enthalpy of the reaction, the sum of molar standard enthalpies of formation of reactants should be subtracted from molar standard enthalpies of formation of products:
A,H" (kJ/mol) = 2 mol x (-241.83 kJ/mol) – 1 mol x
x 50.6 kJ/mol = -534.3 kJ/mol
Convert the value from (kJ mol) to (kJg):
1 mol (N,H4)
32.05 g (N,H,)
A,H" (kJ/g) = -534.3 kJ/mol x
= -16.67 kJ/g
Calculate specific heat of the reaction 1,1-dimethyikydrazine with onygen.
A,H' = 30.06 v kig 1,1-dimethyilhydrazine
Correct
To calculate molar enthalpy of the reaction, the sum of molar standard enthalpies of formation of reactants should be subtracted from molar standard enthalpies of formation of products:
A,H" (kJ/mol) = 2 mol x (-393.509 kJ/mol) + 4 mol x
x (-241.83 kJ/mol) – 1 mol x 48.9 kJ/mol --1803.2 kJ/mol
Convert the value from (kJ mol) to (kg):
1 mol (N3 H3 (CH3)2)
60.10 g (N;H2 (CH,)2)
-30.00 kJ/g
A,H" (kJ/g) = -1803.2 kJ/mol x
Decide whether the reaction of hydrazine or 1,1-dimethyihydrazine with oxygen provides more energy per gram.
O Hydrazine gives more heat per gram when reacting with oxygen.
O1,1-Dimethylhydrazine gives more heat per gram when reacting with oxygen.
O The compounds give almost the same heat per gram when reacting with oxygen.
Transcribed Image Text:Hydrazine and 1,1-dimethylhydrazine both react spontaneously with Oz and can be used as rocket fuels. N3H4() + O2(g) → N2(g) + 2 H2O(g) N,Hạ (CH,)2() +4 0:(8) + 2 CO: (8) + 4 Hạ0(g) + N2(8) The molar enthalpy of formation of N3H,(() is +50.6 kl mol, and that of N3H2 (CH,)2(0) is +48.9 kJ mol. Use these values, with other A,H values in the table below. Compound A H (kJ/mol) H,O(g) CO(8) -241.83 -393.509 Calculate the specific heat of the reaction hydrazine with oxygen. A,H = -16.7 V kig hydrazine Correct To calculate molar enthalpy of the reaction, the sum of molar standard enthalpies of formation of reactants should be subtracted from molar standard enthalpies of formation of products: A,H" (kJ/mol) = 2 mol x (-241.83 kJ/mol) – 1 mol x x 50.6 kJ/mol = -534.3 kJ/mol Convert the value from (kJ mol) to (kJg): 1 mol (N,H4) 32.05 g (N,H,) A,H" (kJ/g) = -534.3 kJ/mol x = -16.67 kJ/g Calculate specific heat of the reaction 1,1-dimethyikydrazine with onygen. A,H' = 30.06 v kig 1,1-dimethyilhydrazine Correct To calculate molar enthalpy of the reaction, the sum of molar standard enthalpies of formation of reactants should be subtracted from molar standard enthalpies of formation of products: A,H" (kJ/mol) = 2 mol x (-393.509 kJ/mol) + 4 mol x x (-241.83 kJ/mol) – 1 mol x 48.9 kJ/mol --1803.2 kJ/mol Convert the value from (kJ mol) to (kg): 1 mol (N3 H3 (CH3)2) 60.10 g (N;H2 (CH,)2) -30.00 kJ/g A,H" (kJ/g) = -1803.2 kJ/mol x Decide whether the reaction of hydrazine or 1,1-dimethyihydrazine with oxygen provides more energy per gram. O Hydrazine gives more heat per gram when reacting with oxygen. O1,1-Dimethylhydrazine gives more heat per gram when reacting with oxygen. O The compounds give almost the same heat per gram when reacting with oxygen.
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