Hydrogen lodide decomposes to form hydrogen and lodine, like this: 2 HI(g) → H₂(g) + L₂(g) Also, a chemist finds that at a certain temperature the equilibrium mixture of hydrogen iodide, hydrogen, and lodine has the following composition: ? compound pressure at equilibrium HI 31.0 atm H₂ 20.7 atm 12 58.5 atm Calculate the value of the equilibrium constant K for this reaction. Round your answer to 2 significant digits. K₁ = 0 0.0 X 3 ol Ar

Hydrogen lodide decomposes to form hydrogen and lodine, like this: 2 HI(g) → H₂(g) + L₂(g) Also, a chemist finds that at a certain temperature the equilibrium mixture of hydrogen iodide, hydrogen, and lodine has the following composition: ? compound pressure at equilibrium HI 31.0 atm H₂ 20.7 atm 12 58.5 atm Calculate the value of the equilibrium constant K for this reaction. Round your answer to 2 significant digits. K₁ = 0 0.0 X 3 ol Ar

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter12: Chemical Equilibrium

Section: Chapter Questions

Problem 60QRT

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