If a solution of a compound (50.0 g/100 mL of solution) has a measured rotation of +150 in a 2 dm tube, the specific rotation is: * +20 O +35 +15 +8 OOO
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A: Specific rotation = observed rotation/(concentration × path length) Observed rotation = -2.47° Mass…
Q: The observed rotation of 2.0 g of a compound in 50 mL of solution in a polarimeter tube 20 cm long…
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Q: If a solution of a compound (50.0 g/100 mL of solution) has a measured rotation of +150 in a 2 dm…
A:
Q: A solution containing 5.0g of compound dissolved in 1000mL of solvent generated an observed rotation…
A: Given data,Observed rotation=27oLength of tube=250mmMass of solute=5.0gVolume of solvent=1000mL
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Q: A solution of (S)-2-butanol (molar mass = 74.12) is observed to have a rotation in a 10.0 cm…
A: Optical rotation = specific rotation × length of the tube × concentration .
Q: What is the specific rotation 20[a ]D of the following molecule? * a = 4.42° C = 0.1g.mr" | = 10cm -…
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Q: 2. The observed rotation of a compound, X (14.0g dissolved in water to make 100ml. of solution) in a…
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Q: A solution of a chiral compound was prepared by dissolving 15.67 g in 16.00 mL of solvent. The…
A: Given data: Observed rotation = 62.41° Path length = 1.00 dm Mass of compound = 15.67 g Volume of…
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Q: What is the specific rotation 20[a ]D of the following molecule? a = 4.42° C = 0.1g.mr1 | = 10cm -…
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- An aqueous solution containing 6.67 g of an optically-pure compound was diluted to 7.00 x 10 mL with water and placed in a 15.0 cm long polarimeter tube. The measured rotation was -2.61° at 25° C. Calculate the specific rotation of the compound. = (α=app:10Tack.co Type here to se OM C O Quin 23 of 30 A solution of a chiral compound was prepared by dissolving 15.67 g in 16.00 mL of solvent. The solution was placed in a tube that is 1.00 dm long. What is the specific rotation of light if the observed rotation was determined experimentally to be +62.41"? ✓ O 1 4 7 2 5 3 6 9 0 DAộ c * ▪ ✪ с x 100 1508227The specific rotation, [a]p, for (-)-2-butanol is +14. What is the observed rotation for a solution of 3.3 g of (-)-2-butanol in 10 mL of water in a sample tube having a pathlength of 10 cm? degrees . The observed rotation of a solution of 0.75 g of a compound in 10 mL of water is -6.9 degrees. If the pathlength is 10 cm, what is the specific rotation of the compound?
- < Question 22 of 67 A solution of a chiral compound was prepared by dissolving 15.67 g in 16.00 mL of solvent. The solution was placed in a tube that is 1.00 dm long. What is the specific rotation of light if the observed rotation was determined experimentally to be +62.41°? 1 4 7 +/- 2 сл 8 . 6 S O Submit C x 100Which of the following compounds has an asymmetric center? II III OIV OV CI H-CH3 CI II Br Br III -H 15 но- H CI IV TENEM -Br E EE 326 LEF V(S)-2-Bromobutane has a specific rotation of +23.1°. Suppose that a solution is made by dissolving 20.00 g of (S)-2-bromobutane in 1.00 L total solution. What would be the measured rotation of plane-polarized light sent througha 10.00-cm tube containing that solution?
- 1. When 0.247 g of monosodium glutamate (MSG) is dissolved in 10.0 mL of water and placed in a sample cell 10.0 cm in length, the observed rotation at 20°(using the D line of sodium) is +0.632°. Calculate the specific rotation of MSG. 2. When 0.095 g of cholesterol is dissolved in 1.00 mL of ether and placed in a sample cell 10.0 cm in length, the observed rotation at 20°C (using the D line of sodium) is -0.299°.Calculate the specific rotation of cholesterol.3. The specific rotation of L-dopa in water (at 15°C) is -39.5. A chemist prepared a mixture of L-dopa and its enantiomer, and this mixture had a specific rotation of -34. Calculate the % ee of this mixture. 4. The specific rotation of vitamin B7 in water (at 22°C) is +92. A chemist prepared a mixture of vitamin B7 and its enantiomer, and this mixture had a specific rotation of +18. Calculate the % ee of this mixture.bë 4 Absorbance of a solution increases with increasing Wavelength Temperature Concentration FrequencyView Policies Current Attempt in Progress When 0.234 g of monosodium glutamate (MSG) is dissolved in 10.0 mL of water and placed in a sample cell 10.0 cm in length, the observed rotation at 20°(using the D line of sodium) is +0.599°. Calculate the specific rotation of MSG. specific rotation = [a] = i eTexthook and Media
- 1. d1= 2 cm d2= 5.2 cm d3= 11.1 cm ds=12 cm Rf= Rf= Rf= Polar: Non Polar 2. d1= 18.1 cm d2= 18.1 cm d3= 18.1 cm ds=20 cm Rf= Rf= Rf= d. Polar: Non Polar 3. d1= 2.1 cm d2= 2.1 cm d3= 2.1 cm ds=18 cm Rf= Rf= Rf= Polar: Non Polar 4. d1= 2.1 cm d2= 10.21 cm d3= 17.213 cm d,=18 cm Rf= Rf= Rf= Polar: Non Polar Distance travelled By the solvent The various dyes1. Determine the R/S configuration of all stereocenters in the following molecules: OH CI CH3 OH土 Ligh=Q + Fe C), रনিो म