-If (S)-2-bromo-3-methylbutane reacts with sodium methoxide (NaOCH) in a mixed solvent made from equal volume of methanol and hexane. The percent of the major product (enantiomer) if the reaction went to completion will be
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- -Ocimene is a pleasant-smelling hydrocarbon found in the leaves of certain herbs. It has the molecular formula C10H16 and a UV absorption maximum at 232 nm. On hydrogenation with a palladium catalyst, 2,6-dimethyloctane is obtained. Ozonolysis of -ocimene, followed by treatment with zinc and acetic acid, produces the following four fragments: (a) How many double bonds does -ocimene have? (b) Is -ocimene conjugated or nonconjugated? (c) Propose a structure for -ocimene. (d) Write the reactions, showing starting material and products.Consider a reaction where cis-but-2-ene is treated with OsO4 followed by NaHSO3/H2O. Draw the structure of one product that is formed in the reaction, including correct stereochemistry.Dehydrohalogenation of 1-chloro-1-methylcyclopropane affords two alkenes (A and B) as products. Explain why A is the major product despite the fact that it contains the less substituted double bond.
- Two products are possible when pent-2-ene is treated with HBr. Write the structures of the possible products, and explain why they are made in about equal amounts.A chemist allows some pure (2S,3R)-3-bromo-2,3-diphenylpentane to react with a solution of sodium ethoxide(NaOCH2 CH3) in ethanol. The products are two alkenes: A (cis-trans mixture) and B, a single pure isomer. Under the same conditions, the reaction of (2S,3S)-3-bromo-2,3-diphenylpentane gives two alkenes, A (cis-trans mixture) and C. Upon catalytic hydrogenation, all three of these alkenes (A, B, and C) give 2,3-diphenylpentane. Determine the structures of A, B, and C; give equations for their formation; and explain the stereospecificity of these reactions.When allyl bromide is refluxed with magnesium metal in ether solvent, the product formed is 1,5-hexadiene. (C6H10). What is the curved arrow mechanism for this reaction?
- Compounds X and Y are both C5H11CI products formed in the radical chlorination of pentane. Base-promoted E2 elimination of X and Y gives, in each case, a single C5H10 alkene (ignoring double bond stereochemistry). Both X and Y react in SN2 fashion with sodium iodide in acetone; Y reacts faster than X. What is the structure of Y? • Do not use stereobonds in your answer. • In cases where there is more than one possible structure for each molecule, just give one for each. • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. • Separate structures with + signs from the drop-down menu. ChemDoodle (Previous NextWrite complete chemical equation showing reactants, products, and catalysts needed (if any) for the following reaction: d) Reaction of cis-3,3-Dimethyl-4-propylocta-1,5-diene with two mole of HBr e) Reaction of trans-1-Bromo-3-chlorocyclopentane with potassium hydroxide f) Formation of Gilman reagent using isopropyl bromide g) Ozonolysis of 3,3-Dimethyloct-4-ynePossible alternative brominations include: Veratrole (1,2-dimethoxybenzene) to 1,2-dibromo-4,5-dimethoxybenzene; 4-Methylacetanilide to 2-bromo-4-methylacetanilide; 2-Methylacetanilide (made in experiment S.1) to 4-bromo-2-methylacetanilide; Vanillin to 5-bromovanillin; Acetanilide to 4-bromoacetanilide; a. b. C. d. e. EXPERIMENT S4: BROMINATION OF AROMATIC COMPOUNDS Certain other acetanilides made in experiment S.1 may also be used as precursors in this experiment. Estimated time: 1 afternoon Associated learning goals: Section 6, LG 6.6; Section 7, LG 7.2 and 7.4 Pre-lab report: complete the standard report form, and answer the following questions. In this experiment, molecular bromine (Br2) is generated from the redox reaction of potassium bromate with hydrobromic acid. Write a balanced equation for this process. Briefly outline the mechanism by which Br2 brominates your aromatic compound. Why do the bromine atoms end up at the positions indicated rather than anywhere else in the…
- Chemistry 60. Give the principal product(s) expected, if any, when trans-1,3-pentadiene reacts under the following conditions. Assume one equivalent of each reagent reacts unless noted otherwise. (a) H2O, H3O+ (b) Na+EtO- in EtOH (c) Maleic anhydride heatAlkyl halides undergo elimination reactions to produce alkenes by the reacting with strong bases as shown in the following reaction (see image). In general, compounds where the halogen is axial (axial position) are much more reactive than those in which they are in the equatorial position. Taking the above into account: a. Which of the following compounds would give a faster elimination reaction: cis-1-bromo-2-tert-butylcyclohexane or trans-1-bromo-2-tert-butylcyclohexane? Draw the corresponding structures and clearly explain the choice.When 2-bromo-2-methylbutane is treated with a base, a mixture of 2-methyl-2-butene and 2-methyl-1- butene is produced. When potassium hydroxide is the base, 2-methyl-1-butene accounts for 45% of the product mixture. However, when potassium tert-butoxide is the base, 2-methyl-1-butene accounts for 70% of the product mixture. What percent of 2-methyl-1-butene would be in the mixture if potassium propoxide were the base? base Br A. Less than 45% B. C. 45% Between 45% and 70% D. More than 70%