If the uniform concrete block has a mass of 500 kg, determine the smallest horizontal force P needed to move the wedge to the left. The coefficient of static friction between the wedge and the concrete and the wedge and the floor is 0.3. The coefficient of static friction between the concrete and floor is 0.5. ANSWER: P = 1797.52 N = 1.80 kN 3 m B 150 mm 7.5° a.) the angle of friction between the wedge and the concrete and the wedge and the floor. Answer: 6wedge and concrete = 6wedge and floor = 16.7° b.) the coefficient of static friction between the concrete and floor. Answer: 0concrete and floor = 263.56° сот

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If the uniform concrete block has a mass of 500 kg, determine the smallest horizontal force P needed to move
the wedge to the left. The coefficient of static friction between the wedge and the concrete and the wedge and
the floor is 0.3. The coefficient of static friction between the concrete and floor is 0.5.
ANSWER: P = 1797.52 N = 1.80 kN
3 m
B
150 mm;
7.5°
a.) the angle of friction between the wedge and the concrete and the wedge and the floor.
Answer: 0wedge and concrete = 0wedge and floor = 16.7°
b.) the coefficient of static friction between the concrete and floor.
Answer: 0concrete and floor = 263.56°
%3D
Transcribed Image Text:If the uniform concrete block has a mass of 500 kg, determine the smallest horizontal force P needed to move the wedge to the left. The coefficient of static friction between the wedge and the concrete and the wedge and the floor is 0.3. The coefficient of static friction between the concrete and floor is 0.5. ANSWER: P = 1797.52 N = 1.80 kN 3 m B 150 mm; 7.5° a.) the angle of friction between the wedge and the concrete and the wedge and the floor. Answer: 0wedge and concrete = 0wedge and floor = 16.7° b.) the coefficient of static friction between the concrete and floor. Answer: 0concrete and floor = 263.56° %3D
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