Implement a subprogram which takes 4 numbers in the argument registers $a0...$a3, and returns the largest value and the average in $v0 and $v1 to the calling program. The program must be structured as follows: Subprogram largestAndAverage($a1, $a2, $a3, $a4) {  int var0 = $a0, var1 = $a1, var2 = $a2, var3 = $a3;  $s0 = getLarger($a1, $a2);  $s0 = getLarger($s0, $a3);  $v0 = getLarager(s0, $a4); // Largest is in $v0  $v1 = (var0 + var1 + var2 + var3)/ 4; // Aversge is in $v1  return; } Subprogram getLarger($a0, $a1) {  $v0 = $a0  if ($a1 > $a0)  $v0 = $a1  return; } Note the use of the variables var0...var3. Because the values of $a0 and $a1 (at least) are changed on the call to getLarger, they will not be available when they are needed to calculate the average, and must be stored on the stack. To do this problem correctly, you must calculate the maximum value using the getLarger subprogram shown here, and it must be called before the average is calculated. This implies that at a minimum $a0 and $a1 must be stored on the stack, though I would suggest all four be stack variables as shown here. It is possible to create a solution which does not require the use of the stack variables, for example by simply calculating the average first. Such solutions do not answer the issue of how to handle variables that change using the stack, and are thus incorrect.

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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Implement a subprogram which takes 4 numbers in the argument registers $a0...$a3, and
returns the largest value and the average in $v0 and $v1 to the calling program. The
program must be structured as follows:
Subprogram largestAndAverage($a1, $a2, $a3, $a4)
{
 int var0 = $a0, var1 = $a1, var2 = $a2, var3 = $a3;
 $s0 = getLarger($a1, $a2);
 $s0 = getLarger($s0, $a3);
 $v0 = getLarager(s0, $a4); // Largest is in $v0

 $v1 = (var0 + var1 + var2 + var3)/ 4; // Aversge is in $v1
 return;
}
Subprogram getLarger($a0, $a1) {
 $v0 = $a0
 if ($a1 > $a0)
 $v0 = $a1
 return;
}
Note the use of the variables var0...var3. Because the values of $a0 and $a1 (at least) are
changed on the call to getLarger, they will not be available when they are needed to calculate
the average, and must be stored on the stack. To do this problem correctly, you must
calculate the maximum value using the getLarger subprogram shown here, and it must be
called before the average is calculated. This implies that at a minimum $a0 and $a1 must be
stored on the stack, though I would suggest all four be stack variables as shown here.
It is possible to create a solution which does not require the use of the stack variables, for
example by simply calculating the average first. Such solutions do not answer the issue of
how to handle variables that change using the stack, and are thus incorrect.

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