In a Leichtman Research Group survey of800TV households,74.8%of them had at least one Internet-connected TV device (for example, Smart TV, standalone streaming device, connected video game console). A marketing executive wants to convey high penetration of Internet-connected TV devices, so he makes the claim that the percentage of all homes with at least one Internet-connected TV device is equal to79%.Test that claim using a0.01significance level. Use the P-value method. Use the normal distribution as an approximation to the binomial distribution. Question content area bottomPart 1Let p denote the population proportion of all homes with at least one Internet-connected TV device. Identify the null and alternative hypotheses. H0:p▼ less than<equals=greater than>not equals≠enter your response hereH1:p▼ not equals≠less than<equals=greater than>enter your response here(Type integers or decimals. Do not round.)Part 2Identify the test statistic. z=enter your response here(Round to two decimal places as needed.)Part 3Identify the P-value. P-value=enter your response here(Round to three decimal places as needed.)Part 4State the conclusion about the null hypothesis, as well as the final conclusion that addresses the original claim. ▼ AcceptRejectFail to rejectthe null hypothesis. There▼ isis notsufficient evidence to▼ supportwarrant rejection ofthe claim that the percentage of all homes with at least one Internet-connected TV device is equal to79%.

given data, n=800p^=0.748claim:p=0.79α=0.01

Answered: In a Leichtman Research Group survey of…

Holt Mcdougal Larson Pre-algebra: Student Edition 2012

1st Edition

ISBN:9780547587776

Author:HOLT MCDOUGAL

Publisher:HOLT MCDOUGAL

Chapter11: Data Analysis And Probability

Section: Chapter Questions

Problem 8CR

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Question content area bottom

Part 1

Let p denote the population proportion of all homes with at least one Internet-connected TV device. Identify the null and alternative hypotheses.

H0:

▼

less than<

equals=

greater than>

not equals≠

enter your response here

H1:

▼

not equals≠

less than<

equals=

greater than>

enter your response here

(Type integers or decimals. Do not round.)

Part 2

Identify the test statistic.

z=enter your response here

(Round to two decimal places as needed.)

Part 3

Identify the P-value.

P-value=enter your response here

(Round to three decimal places as needed.)

Part 4

State the conclusion about the null hypothesis, as well as the final conclusion that addresses the original claim.

▼

Reject

Fail to reject

the null hypothesis. There

▼

is not

sufficient evidence to

▼

support

warrant rejection of

the claim that the percentage of all homes with at least one Internet-connected TV device is equal to

79%.

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

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