In a particular experiment, it was found that when O₂(g) and CO(g) were mixed and allowed to react according to the equation 2CO(g) + O₂(g) → 2CO₂(g) the O₂ concentration had decreased by 0.041 mol L-1 when the reaction reached equilibrium. How had the concentrations of CO and CO₂ changed? [CO] decrease = i [CO₂] increase = i mol/L mol/L

Chemistry for Engineering Students
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Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 12.103PAE: 12.103 Methanol, CH3OH, can be produced by the reaction of CO with H2, with the liberation of heat....
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In a particular experiment, it was found that when O₂(g) and CO(g) were mixed and allowed to react according to the equation
2CO(g) + O₂(g) → 2CO₂(g)
the O₂ concentration had decreased by 0.041 mol L-¹ when the reaction reached equilibrium. How had the concentrations of CO and
CO₂ changed?
[CO] decrease =
[CO₂] increase =
mol/L
mol/L
Transcribed Image Text:In a particular experiment, it was found that when O₂(g) and CO(g) were mixed and allowed to react according to the equation 2CO(g) + O₂(g) → 2CO₂(g) the O₂ concentration had decreased by 0.041 mol L-¹ when the reaction reached equilibrium. How had the concentrations of CO and CO₂ changed? [CO] decrease = [CO₂] increase = mol/L mol/L
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