In a survey of 400400 likely​ voters, 216216 responded that they would vote for the incumbent and 184184 responded that they would vote for the challenger. Let p denote the fraction of all likely voters who preferred the incumbent at the time of the​ survey, and let ModifyingAbove p with caretp be the fraction of survey respondents who preferred the incumbent.   Using the survey​ results, the estimated value of ModifyingAbove p with caretp is 0.54000.5400. ​(Round your response to four decimal places.​) Part 2 Using ModifyingAbove p with caretp​(1minus−ModifyingAbove p with caretp​)/n as the estimator of the variance of ModifyingAbove p with caretp​, the standard error of the estimator is 0.02700.0270. ​(Round your response to four decimal places.​) Part 3 The p​-value for the test Upper H Subscript o Baseline : p equals 0.5 versus Upper H 1 : p not equals 0.5Ho: p=0.5 versus H1: p≠0.5 is 0.13840.1384. ​(Round your response to three decimal places.​) Part 4 The p​-value for the test Upper H Subscript o Baseline : p equals 0.5 versus Upper H 1 : p greater than 0.5Ho: p=0.5 versus H1: p>0.5 is enter your response here. ​(Round your response to three decimal

Essentials of Business Analytics (MindTap Course List)
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ISBN:9781305627734
Author:Jeffrey D. Camm, James J. Cochran, Michael J. Fry, Jeffrey W. Ohlmann, David R. Anderson
Publisher:Jeffrey D. Camm, James J. Cochran, Michael J. Fry, Jeffrey W. Ohlmann, David R. Anderson
Chapter6: Statistical Inference
Section: Chapter Questions
Problem 21P: The Pew Research Center Internet Project conducted a survey of 857 Internet users. This survey...
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In a survey of
400400
likely​ voters,
216216
responded that they would vote for the incumbent and
184184
responded that they would vote for the challenger. Let p denote the fraction of all likely voters who preferred the incumbent at the time of the​ survey, and let
ModifyingAbove p with caretp
be the fraction of survey respondents who preferred the incumbent.
 
Using the survey​ results, the estimated value of
ModifyingAbove p with caretp
is
0.54000.5400.
​(Round
your response to four decimal
places.​)
Part 2
Using
ModifyingAbove p with caretp​(1minus−ModifyingAbove p with caretp​)/n
as the estimator of the variance of
ModifyingAbove p with caretp​,
the standard error of the estimator is
0.02700.0270.
​(Round
your response to four decimal
places.​)
Part 3
The
p​-value
for the test
Upper H Subscript o Baseline : p equals 0.5 versus Upper H 1 : p not equals 0.5Ho: p=0.5 versus H1: p≠0.5
is
0.13840.1384.
​(Round
your response to three decimal
places.​)
Part 4
The
p​-value
for the test
Upper H Subscript o Baseline : p equals 0.5 versus Upper H 1 : p greater than 0.5Ho: p=0.5 versus H1: p>0.5
is
enter your response here.
​(Round
your response to three decimal
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