In a typical one trait experiment of Mendel's, yellow pureline peas (YY) are crossed with green pureline peas (yy). The offspring are yellow. Then, those offspring are selfed. Which statements are / would be true about this experiment?
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Q: a) 50% homozygous dominant, 50% heterozygous
A: Answer:(A) 50% homozygous dominant, 50%heterozygous
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A: This is a case of dihybrid cross because two genes are involved in this cross.
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A: Alleles are variants of a gene. An allele may be dominant or recessive. The inheritance of two…
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- Genetics Problems. Show your crosses. It must contain: (a) parental genes, (b) genotypic ratio, (c) phenotypic ratio, (d) hybrid cross and (e) other answer needed in the question. A. Let us consider two sex-influenced traits simultaneously, pattern baldness and short index finger, both of which are dominant in men and recessive in women. A heterozygous bald man with long index finger marries a heterozygous long-fingered, bald woman. Determine the phenotypic expectations for their children.O e. Parent 2: Parent 1: Parent 2: ¡Ai QUESTION 9 Bi QUESTION 8 Let's assume that, in dragons, red scales (B) are dominant to green scales (b), and long tongues (S) are dominant to short tongues (s). The genes that determine these characteristics assort independently. A homozygous red, long-tongued dragon is crossed with a homozygous green, short-tongued dragon. If an F1 dragon is crossed to a homozygous green and homozygous short-tongued dragon, what phenotypes and proportions are expected in the offspring? O a. 100% green and long-tongued O b. ½ green and short-tongued & ½ red and long-tongued O c. ½ red and short-tongued & ½ green and long-tongued O d.% red and long-tongued, % red and short-tongued, ½ green and long-tongued, % green and short-tongued O e. 9/16 red, long-tongued, 3/16 green, long-tongued, 3/16 red, short-tongued, 1/16 green, short-tongued Save and Submit to save and submit. Click Save All Answers to save all answers. 000 MacBook AirGenetics Problems. Show your crosses. It must contain: (a) parental genes, (b) genotypic ratio, (c) phenotypic ratio, (d) hybrid cross and (e) other answer needed in the question. An albino is a person with no pigmentation in his skin, eyes or hair. Normal pigmentation is (A) is dominant over albino (a). A normal pigmented man marries a homozygous normal woman. What would the expected appearances of the children be
- Two Manx cats mate. Manx allele is dominant but is lethal in homozygous individuals. What is the probability that the first three offspring will display the wild-type phenotype (non-Manx)? Show your work including a Punnett square.You breed two black dogs. It results in 3 offspring, the first which is black, the second which is brown, and the third which is white. Give two genetic explanations as to what could cause their fur color. Make sure each explanation includes two genes and follows along with the provided data. Also, explain the genotype of each color of dog and a ratio of the F2 phenotypes you would expect to see from a dihybrid cross. After you're finished, pick one of the explanations and create a hypothesis for the function of each gene which would explain the molecular basis of the fur color Finally, for each of the two genes, explain how a specific functional difference between the two alleles leads to a difference in their functionsIncomplete Dominance 1. In snapdragons, red flower color (R) is incompletely dominant over white flower color (r). The hybrids or heterozygous plants (Rr) are pink in color. a) Show the genotype for a white flower and for a red flower. b) If a red-flowered plant is crossed with a white-flowered plant, what are the genotypes and phenotypes of the F1 generation plants? Show your work. c) What genotypes and phenotypes will be produced in the F2 generation? Show your work? the the o doa A t r th s beirs ard the phenorypic and wo ran aials pring fro d) How did the genotypic and phenotypic ratio compare to each other in this incomplete dominance cross? gonarypi and e) What would the phenotypic ratio have been if this had been complete dominance?
- 3. Short-tailed pup distribution. In mice, the dominant T allele results in a short tail. Homozygous T/T genotype is lethal, which means mouse embryos with this genotype die before they are born. Homozygous t/t is normal, with normal tail. A cross between two short-tailed mice produces a litter of 5 pups. a). What are the genotype(s) of the two short-tailed mice used in the cross? b). What are the possible genotypes and phenotypes of the 5 pups? What are their perspective ratio?Genetics 181 Rule of Incomplete Dominance When two different pure-breeding strains are crossed, and their offspring show a blending of phenotypes, then neither allele is dominant. This is easily recognized when the phenotype is somewhere between two extremes. Counting the parents, there are three phenotypes (black, white, grey) being expressed in these flowers instead of only two, and that third phenotype is intermediate between the other two. This heterozygous condition is called incomplete dominance. 1. On the chart you did earlier, which of the three hair types (wavy, curly, or straight) represents incomplete dominance-the blended heterozygous condition? 2. You cross a herd of red cattle with white cattle and all of the calves appear to be roan (reddish white). Is this an example of incomplete dominance? How do you know? 3. You cross a blue flowering pea plant with a white flowering pea plant and all of the offspring are blue flowered. Is this an example of incomplete dominance? How…TEST goo.g/CUYGKD 2.) A man with type A blood marries a woman with type B blood. Their child has type O blood. What are the genotypes of these three individuals? What genotypes, and in what frequencies, would you expect in future offspring from this marriage? 3. A man has six fingers on each hand and six toes on each foot. His wife and their daughter have the normal number of digits. Remember that extra digits is a dominant trait. What fraction of this couple's children would be expected to have extra digits?
- Inheritance of a single gene: 7. A tortoiseshell cat mates with an orange cat: What is the probability of their kitten having all-orange fur? [Choose ] [Choose ] 0.25 What is the probability of their kitten having tortoiseshell coloration? 0.5 0.875 1.0 0.625 What is the probability of their kitten having all-black fur? 0.375 0.33 0.75 What is the probability that their black kitten will be male? [Choose ] What is the probability that their tortoiseshell kitten will be male? [Choose ]Dihybrid Cross Practice In a breed of dog called a Doberman, black fur is dominant to brown fur and floppy ears are dominant to straight ears. These letters represent the genotypes and phenotypes of the dogs: EE = floppy ears Ee = floppy ears bb = brown fur ee = pointed ears BB = black fur %3D Bb = black fur 1. A female dog with the genotype BBee is crossed with a male dog with the genotype bbEe The square is set up below. Fill it out and determine the phenotypes and proportions in the offspring. Ве Ве Ве Ве bE How many out of 16 have: black fur and floppy ears? be black fur and pointed ears? brown fur and floppy ears? bE brown fur and pointed ears? beURGENT PLEASE HELP A researcher crosses mice with brown eyes and long tails, and the F1 progeny were recovered in the following numbers and phenotypic classes:F1: 6 apricot, short : 30 brown, long : 15 brown, short : 9 apricot, longYou know the genes encoding these traits are autosomal, completely dominant and assort independently. You want to use a chi-square test to analyse these results.a) Making use of the appropriate genetic convention for naming alleles, give the genotype of the male parent in this cross. b) What is your null hypothesis for the chi-square test? c) Give the expected number of individuals in the “brown, long” class.