In the titration of 60.0 mL of 1.0 M methylamine, CH3NH₂ (Kb = 4.4 x 10-4), with 0.50 M HCI, calculate the pH under the following conditions. (a) after 0.00 mL of 0.50 M HCI has been added 4.0 (b) after 20.0 mL of 0.50 M HCI has been added 4.0 (c) after 60.0 mL of 0.50 M HCI has been added 4.0✔

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Chapter16: Acid-base Equilibria
Section: Chapter Questions
Problem 16.144QP
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In the titration of 60.0 mL of 1.0 M methylamine, CH3NH₂ (K₁ = 4.4 x 10-4), with 0.50 M HCI, calculate the pH under the
following conditions.
(a) after 0.00 mL of 0.50 M HCI has been added
4.0
(b) after 20.0 mL of 0.50 M HCI has been added
4.0✔
(c) after 60.0 mL of 0.50 M HCI has been added
4.0✔
(d) at the stoichiometric point
4.0✔
(e) after 200.00 mL of 0.50 M HCI has been added
4.0
Transcribed Image Text:In the titration of 60.0 mL of 1.0 M methylamine, CH3NH₂ (K₁ = 4.4 x 10-4), with 0.50 M HCI, calculate the pH under the following conditions. (a) after 0.00 mL of 0.50 M HCI has been added 4.0 (b) after 20.0 mL of 0.50 M HCI has been added 4.0✔ (c) after 60.0 mL of 0.50 M HCI has been added 4.0✔ (d) at the stoichiometric point 4.0✔ (e) after 200.00 mL of 0.50 M HCI has been added 4.0
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