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- Find an equation of the tangent line to the curve at the given point.y = 4x^2 − x^3, (1, 3) Illustrate by graphing the curve and the tangent line on the same screen.Find an equation of the tangent line to the curve at the given point. Y= x^3 -3x+2, (2,4)find an equation of the tangent line that passes through y=x^3+x+4 at (-(2,-6)
- Find the slope and an equation of the tangent line to the graph of the function f at the specified point. F(x)= -9/2x^2+4x+4; (-1,-9/2) slope= equation y=Find the equation of the line tangent to the function at the given point. Your answer should be in slope intercept form y=x^3-2x^2+2 at (2,2)|Find an equation of the tangent line to the curve at the given point.y=8x-6x^(2), P(4,-8)