ir is to be cooled in the evaporator section of a refrigerator by passing it over a bank of 0.8 n-long tubes inside which the refrigerant is evaporating at -20°C. Air approaches the tube °C and 1 atm with a mean velocity of 5 m/s. The tubes are arranged staggered with longitu L = ST = 1.5 cm. There are 25 rows in the flow direction with 15 tubes in each row. Assume 5°C and the properties of air at this temperature and 1 atm are (Table A-15) k = 0.02326 W/t 316 kg/m3, Pr = 0.7375, µ = 1.705 × 10¬5 kg/m-s, and Prs = Pr@ Ts = -20°C = 0.7408. Also, th emperature of O°C (for use in the mass flow rate calculation at the inlet) is pi = 1.292 kg/m³.
ir is to be cooled in the evaporator section of a refrigerator by passing it over a bank of 0.8 n-long tubes inside which the refrigerant is evaporating at -20°C. Air approaches the tube °C and 1 atm with a mean velocity of 5 m/s. The tubes are arranged staggered with longitu L = ST = 1.5 cm. There are 25 rows in the flow direction with 15 tubes in each row. Assume 5°C and the properties of air at this temperature and 1 atm are (Table A-15) k = 0.02326 W/t 316 kg/m3, Pr = 0.7375, µ = 1.705 × 10¬5 kg/m-s, and Prs = Pr@ Ts = -20°C = 0.7408. Also, th emperature of O°C (for use in the mass flow rate calculation at the inlet) is pi = 1.292 kg/m³.
Principles of Heat Transfer (Activate Learning with these NEW titles from Engineering!)
8th Edition
ISBN:9781305387102
Author:Kreith, Frank; Manglik, Raj M.
Publisher:Kreith, Frank; Manglik, Raj M.
Chapter6: Forced Convection Over Exterior Surfaces
Section: Chapter Questions
Problem 6.42P
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The pressure drop across the tube bank is? use graph for f factor.
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