ir is to be cooled in the evaporator section of a refrigerator by passing it over a bank of 0.8 n-long tubes inside which the refrigerant is evaporating at -20°C. Air approaches the tube °C and 1 atm with a mean velocity of 5 m/s. The tubes are arranged staggered with longitu L = ST = 1.5 cm. There are 25 rows in the flow direction with 15 tubes in each row. Assume 5°C and the properties of air at this temperature and 1 atm are (Table A-15) k = 0.02326 W/t 316 kg/m3, Pr = 0.7375, µ = 1.705 × 10¬5 kg/m-s, and Prs = Pr@ Ts = -20°C = 0.7408. Also, th emperature of O°C (for use in the mass flow rate calculation at the inlet) is pi = 1.292 kg/m³.

Principles of Heat Transfer (Activate Learning with these NEW titles from Engineering!)
8th Edition
ISBN:9781305387102
Author:Kreith, Frank; Manglik, Raj M.
Publisher:Kreith, Frank; Manglik, Raj M.
Chapter6: Forced Convection Over Exterior Surfaces
Section: Chapter Questions
Problem 6.42P
icon
Related questions
Question

The pressure drop across the tube bank is? use graph for f factor.

Required information
Air is to be cooled in the evaporator section of a refrigerator by passing it over a bank of 0.8-cm-outer-diameter and 0.8-
m-long tubes inside which the refrigerant is evaporating at -20°C. Air approaches the tube bank in the normal direction at
0°C and 1 atm with a mean velocity of 5 m/s. The tubes are arranged staggered with longitudinal and transverse pitches of
SI = ST = 1.5 cm. There are 25 rows in the flow direction with 15 tubes in each row. Assume the mean temperature as
-5°C and the properties of air at this temperature and 1 atm are (Table A-15) k= 0.02326 W/m-K, Cp= 1.006 kJ/kg-K, p=
1.316 kg/m3, Pr = 0.7375, µ = 1.705 × 10-5 kg/m-s, and Prs = Pra Ts =-20°C = 0.7408. Also, the density of air at the inlet
temperature of 0°C (for use in the mass flow rate calculation at the inlet) is pj = 1.292 kg/m³.
NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part.
0°C
1 atm
V m/s
0.8 m
Air
Sr= 1.5 cm
0.8 cm
S, = 1.5 cm/
Refrigerant, –20°C
Transcribed Image Text:Required information Air is to be cooled in the evaporator section of a refrigerator by passing it over a bank of 0.8-cm-outer-diameter and 0.8- m-long tubes inside which the refrigerant is evaporating at -20°C. Air approaches the tube bank in the normal direction at 0°C and 1 atm with a mean velocity of 5 m/s. The tubes are arranged staggered with longitudinal and transverse pitches of SI = ST = 1.5 cm. There are 25 rows in the flow direction with 15 tubes in each row. Assume the mean temperature as -5°C and the properties of air at this temperature and 1 atm are (Table A-15) k= 0.02326 W/m-K, Cp= 1.006 kJ/kg-K, p= 1.316 kg/m3, Pr = 0.7375, µ = 1.705 × 10-5 kg/m-s, and Prs = Pra Ts =-20°C = 0.7408. Also, the density of air at the inlet temperature of 0°C (for use in the mass flow rate calculation at the inlet) is pj = 1.292 kg/m³. NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. 0°C 1 atm V m/s 0.8 m Air Sr= 1.5 cm 0.8 cm S, = 1.5 cm/ Refrigerant, –20°C
80
60
40-
Pr= 1.25
1.6
2아1.5.
Repmax = 10²
1.4
2105
10
103
6.
1.2
|2.0
104
10
1.0
102
2105
0.4
0.6 0,8 I
2.
0.8
0.6
0.4
2.5
0.2
Sp = Sr
3.5
0.1
4 6 810! 2 4 68102 2 4 6 810³ 2 4 6 8104 2 4 68 105 2
4 6 8106 2
Rep,max
(b) Staggered arrangement
Friction factor, f
Transcribed Image Text:80 60 40- Pr= 1.25 1.6 2아1.5. Repmax = 10² 1.4 2105 10 103 6. 1.2 |2.0 104 10 1.0 102 2105 0.4 0.6 0,8 I 2. 0.8 0.6 0.4 2.5 0.2 Sp = Sr 3.5 0.1 4 6 810! 2 4 68102 2 4 6 810³ 2 4 6 8104 2 4 68 105 2 4 6 8106 2 Rep,max (b) Staggered arrangement Friction factor, f
Expert Solution
steps

Step by step

Solved in 2 steps with 2 images

Blurred answer
Knowledge Booster
Pressure Vessels
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Principles of Heat Transfer (Activate Learning wi…
Principles of Heat Transfer (Activate Learning wi…
Mechanical Engineering
ISBN:
9781305387102
Author:
Kreith, Frank; Manglik, Raj M.
Publisher:
Cengage Learning