8. lim (7? + 4) 9. lim V2x - x 1024 sin (x + h) - sin x 10. lim where x is a constant h x³ + 4x? + 4x + 3 3 - V5 + x 11. lim 12. lim x + 2x - 3 x41 - V5 -: Vx² + 8 – V5 - 4x * - 9) 16 13. lim 14. lim x + 1 - 4 x- 3 x-2 Va + x - Va 0 xVala + x) 3 tan x - &r 15. lim 16. lim 0 3x + sin 2x (x² – 9)(x² + 4) 3 21? - 3x - 9 sin x 17. lim 18. lim /2 cos x Vi - Va -(;-) sin 19. lim 20. lim a Vr - Va =/3 2 cos x - 1

Q: 2 cos(4x) – 4x2 – 2 lim - I→0 sin(2x)- x2 - 2x

A: We have to evaluate the limit limx→0 2 cos(4x) - 4x2 - 2sin(2x) - x2 - 2x

Q: 3x+7 sin2x x+x.cosx 1- lim- x2-2 lim 2x2+x 3 - lim- x→0 2 - 00+X x→0 sinx.cosx 1 lim x-1- 1-x2 x-3…

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Q: /1+cos x + V1- cos x X =-+÷,0<x<“ 4 2 V1+ cos x - V1-cos x - cOs X

A: Using trigonometry formulas we solve here given question

Q: 2- i) By using L'Hopital Rule, find sinx lim x-0 e3x – 1 ii) Given that a = sin-1 , find ,csca

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Q: 8 sin 3+ 5/ is equal to The number lim | sin(x) dx E. 5. 8 sin(x)dx 8 | sin(x) dx 3. 0 8 8. sin(x)…

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Q: 2x[ cos (3x) – 1] sin (6x) – 6x Use L'Hopital's Rule to evaluate lim 2x[cos (3x) – 1] lim sin (6x) –…

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Q: lim x → ∞ cos(16/x)^(13.32x^2)

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Q: Limits of quotients Find the limits in Exercises 23–42.

A: 23)  Given  Here factors of denominator is x2 -25 = (x-5) (x+5)  Cancel out the (x-5) factor  Now…

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A:

Q: Given y = 4 cos(x) - x. Determine where the function is increasing in [-2, 7]

A: Given y = 4 cos(x) - x

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A:

Q: Calculating LimitsFind the limits in Exercises 11–22.

A: We’ll answer the first question since the exact one wasn’t specified. Please submit a new question…

Q: COs x lim 1 (b) In(2/9) – In(x(1 – x)) x – 2/3 - - lim x→2/3 (c) lim r(tan x2 - In x lim x0+ x In(1+…

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Q: エ→2 x² -4 1- cos 2x 7) lim X sin x エ→0

A: Since you have asked multiple question, we will solve the first question for you as per our guide…

Q: ON 3 sec3(In x) + sec2(In x) tan(In x) 2х n x) tan(In x) n x) dx c³(In x) + sec²(In x)

A: We have to choose the correct option according to the given information

Q: Can you solve number 23

A: The given expression:

Q: 1-cos 2x lim x2 sec x-tan x lim X→0 X→- 2 x- 2 x2 +sin 3x lim 2x+tan 2x . х-0

A: We are solving first question for you. If you want solution for any other question than please…

Q: 9. lim(1+ sin²x)x X-0

A:

Q: Limits at infinity Evaluate the following limits or state thatthey do not exist.

A: Hello! thank you for the question but as per our honor code, we'll able to solve only the first…

Q: Proof 2: 14 sin x dx tan xdx = /6 COs x 1 -= sec x dv = sin xdx cos x du = sec x tan xdx v =-cos x…

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Q: |- lim メ→ X-3 2. lim メ→2 (会 4 メー2 メ*-4 3. lim メ→。 3メ - S;u4X 4. lim メ→。 tau3X 5- lim 1- Cose Sin'e

A: Since you have asked multiple questions. So, we are solving first few for you. If you want any…

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Q: Vx 6. lim x00 In(x1000) 7. lim 3*-2x X0 x2-x 8. lim 35 sin (nx) cos2 (Tx) 9. lim X-5 2n2(x-5)2

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Q: x3 + x2 ) lim x→-1 x+ 1| (i) ( 3 Vx2 +x +6+ Vx + 8 - 5x (ii) 6) lim x1+ x2 – x (iii) ( sin(3x)…

A: Since you have posted a question with multiple sub-parts, we will solve first three sub-parts for…

Q: x cos (3x – 7) cos(2x+ 7) lim cos(플-x)

A: Limits

Q: x*sin (2x) dx a. ** cos(2x) – x³ sin(2x) –r² co. 3 x² cos(2x) +x sin(2x) +- cos(2x) + C 4 1 cos(2x)…

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Q: 1-e2x 10. lim X0 1-ex x2-3x-28 4. lím エ→アーx-14x+49 11. lim In(x sin x) ズ→0 5. lim V2x + 1T ズ→4 12.…

A: Note: Since you have posted multiple questions we will solve the first question for you. If you want…

Q: (7x – 10,* lim x+0 7x lim 2x sin- 9 sin 27x lim x2 21x lim x+00 12 – 3x

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Q: x2-4 1) lim x-2 x-2 sin 2x 2) lim 1 3) lim(-- x0 x V

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Q: Evaluate:* x + 4x lim x4x2 + 2x - 8 4/5 1/2 2/3 3/4 Differentiate with respect to x: * y = sec(x² +…

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Q: 2 sin (4x) lim 2. x2 (1+ cos x)

A: Since you have asked multiple questions in single request  so we  will be answering only first…

Q: (1) x3 – - 13x + 12 5- V4 + 3x lim lim x-3 x3-14x + 15 (3) 7- x x-7 2x*- 6x3 + x2 +3 2x2 - 3x lim…

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Q: x²+1 4.limx→0 x+cosx 1 х3—1 5.limx→1 х-1 9 – x2 maa - 6. lim x→3 V3 + 2x – x² x4-16 7.limx→2 V x³-8

A: according to our guidelines we can answer only three subparts, or question and rest can be…

Q: Proove: Yn- n-1 x

A: Given That : Let us assume that  y=xnlog(x) Prove that : yn=n!x using Leibnitz  theorem

Q: 1-cos (x-T) lim x→T(x-T)sin (x-π)

A: Given limit, limx→π1-cosx-πx-πsinx-π

Q: 2x + Vx x² + 4x 3 1. lim 2. lim 7x2 + 2 sin x 3. lim x→-o x + e* 4. lim et 2xe2x In x 6. lim 5. lim…

A: To decide whether the given limit produces an indeterminate form6. limx→∞lnxx

Q: sech x+csch x Q3: prove that e2x %3D csch x-sech x

A:

Q: 1. Lim 2×ー2xーメ+1 x-x3- 2x + 2 3. Lim メ→。 |- Cos X X-1 Sin 2x 2. Lim csc ax Csc 2x 4. Lim 7X 2x+5 x-…

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Q: lim x->-7  (-x-7)/(4-√(9-x)) lim x->-infinity (√6x^2 - 2x)/(x+8) lim x->0 (7x cos x + sin 5x)/3x

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Q: 2 tan (3x²) 1- _ 2 tan c∞) 2 teanCo lím %3D メ→の 7x2 の -> 6X Ifm a tan (3x) lim 2-1 +3x) x70 x 70 14x…

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Q: limit as x approaches 0 of x^6*cos(4/x)

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Q: V+12-4 3 .lim X-2 tan3x 2. lim X-0 sinax 4). lim X00 x-7x+1 x-2

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Q: 2x² + x + 3 x³ + x dx In[x] + In (x² + 1) + tan^³(x) + C Option 1 3 In]x] +In (x² + 1) + tan¹(x) + C…

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Q: 2-27 1- lim X-3 2-9 2-2x2+1 2- lim -0 -2 Vx+25-5 3- lim sin2x? 4- lim x-0 x sin x 5- lim X-0 2-2cosx

A: 1.

Q: 2x +5x-3 1. lim 6x -7x + 2 4x-6x+3 lim 16x +8x-7 4. x'+8 7. lim 2x-16 1 -1) h-0 hV1+h 10. lim ) sin…

A: 1) Here, the direct substitution  of the limit value will lead the denominator of the function to be…

Q: Limits with Three VariablesFind the limits in Exercises 25–30

A: Dear student, since you have posted multiple questions, as per our policy we will answer first…

Q: 5. y = tan-¹tan x] ab 6. f(x) = x² cos-¹¹-√x²-1 7. f(x) = tan ¹(sin² (2x)) 8. y = (cot ¹(sin¹(x))³

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Q: 1-cos 2X lim x→0 x2 sec x-tan x lim X→- X- 2 x2+sin 3x lim r20 2x+tan 2x

A:

Q: X-2 lim = 2 a. By L'Hopital's Rule, x→² X²-1 1 1 lim = x→2 2x 4

A:

Limits

When it comes to calculus, limits are considered to be a very important topic of discussion. The main importance of limit lies in expressing the value of a function as it gets closer to a certain value. Also, limits can help you to understand other topics, such as continuity and differentiability better. In a broader sense, every calculus notion is a limit. Other branches of calculus have also been derived from limits.