Many of the color varieties of summer squash are determined by two different interacting genes A and B: AA or Aa gives white colored squash, aaBB or aaBb gives yellow squash, and aabb produces green squash. A plant producing white squash is self-crossed. Three fourths of the offspring produces white squash; one fourth produces green squash. What is the genotype of the parent plant producing white squash?
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Many of the color varieties of summer squash are determined by two different interacting genes A and B: AA or Aa gives white colored squash, aaBB or aaBb gives yellow squash, and aabb produces green squash. A plant producing white squash is self-crossed. Three fourths of the offspring produces white squash; one fourth produces green squash. What is the genotype of the parent plant producing white squash?
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- Figure 8.10 In pea plants, purple flowers (P) are dominant to white (p), and yellow peas (Y) are dominant to green (y). What are the possible genotypes and phenotypes for a cross between PpYY and ppYy pea plants? How many squares would you need to complete a Punnett square analysis of this cross?Many of the color varieties of summer squash are determined by two different interacting genes A and B: AA or Aa gives white colored squash, aaBB or aaBb gives yellow squash, and aabb produces green squash. A plant producing white squash is crossed with a plant producing green squash. One half of the offspring produces white squash; the other half produces green squash. What is the genotype of the parent plant producing white squash? AAbb AABB AaBb Aabb AaBBIn corn, seedling color is determined by genes at two loci (C/c and D/d). Suppose that you cross a pure-breeding green seedling with a pure-breeding yellow seedling and obtain only green seedlings in the F1 generation. You then cross two of the F1 seedlings and obtain the following progeny for the F2 generation: 138 green seedlings, 33 virescent-white seedlings, and 10 yellow seedlings. What form of epistasis would explain these data?
- Three recessive traits in garden pea plants are as follows: yellow pods are recessive to green pods, bluish green seedlings are recessive to green seedlings, creeper (a plant that cannot stand up) is recessive to normal. A true breeding normal plant with green pods and green seedlings was crossed to a creeper with yellow pods and bluish green seedlings. The F1 plants were then crossed to creepers with yellow pods and bluish green seedlings. The following results were obtained for the F2 offspring: 2059 green pods, green seedlings, normal 151 green pods, green seedlings, creeper 281 green pods, bluish green seedlings, normal 15 green pods, bluish green seedlings, creeper 2041 yellow pods, bluish green seedlings, creeper 157 yellow pods, bluish green seedlings, normal 282 yellow pods, green seedlings, creeper 11 yellow pods green seedlings, normal Construct a genetic map that shows the…In pea plants, yellow seeds (Y) are dominant to green seeds (y) and round seeds (R) are dominant to wrinkled seeds (). The genes for seed color and seed shape are on different chromosomes. Two true-breeding parents, one with yellow round peas and the other with green wrinkled peas, are crossed to produce a hybrid (heterozygous) F₁. Two F₁ individuals are crossed to give an F2; this is depicted in the Punnett square below. Place the correct genotypes in the Punnett square and the place the correct phenotypic ratios next to their appropriate phenotype on the right. YYRR YYRr YyRR YYrr yyRR yyRr Yyrr YyRr 3/16 1/16 yyrr 9/16 3/16 1/4 E 1/2 16/16 YR ✪✪✪ Yr yR YYRR Y YyRr Yr yR YR YYRr YYRR YyRr yr YyRr yyrr yr YyRr Yyrr yyRr F2 phenotype Phenotypic ratio AA type of tomato (Solanum lycopersicum) produces fruit in three possible colors: red, orange, and green. You cross a true-breeding red-fruited plant with a true-breeding green-fruited plant, and all the F1 offspring are red. You intercross the red F1s, and the resulting F2 generation consists of 61 red-, 13 orange-, and 6 green-fruited plants. a) Assign the phenotypes to a modified 9:3:3:1 ratio (do not just calculate the actual ratio of the phenotypes). Show your work.
- In Primula vulgaris (primrose), purple flowers are dominant to white flowers, and short plants are dominant to tall plants. The genes controlling these two traits are on different chromosomes. You cross a true-breeding purple, short plant with a true-breeding white, tall plant and then intercross the resulting F1 offspring. In the F2 offspring, you find the following phenotypes: Purple, short Purple, tall 608 161 White, short White, tall 173 58 With your knowledge of the x' test, you will determine whether the outcomes of the F1 intercross corresponds to expectations based on Mendelian genetics. 1. What is your null hypothesis for the outcome of the F1 intercross? Write it here: 2. Based on your null hypothesis, how many individuals do you expect in each of the phenotypic classes? Write your expectations below. Purple, short Purple, tall White, short White, tall 3. What are the degrees of freedom for this test? Write your answer here:A certain species of morning glories produces flowers that are blue, red, or purple. Two pure-breeding purple lines are crossed and produce F1 progeny that all make blue flowers. The F1 are allowed to self and produce 320 F2 progeny with the following distribution: 185 blue, 115 purple, and 20 red. Which the following is NOT consistent with this information? A) Red-flowering plants are homozygous recessive for both genes. B) The pure-breeding parental parents are homozygous recessive for mutations in two different genes. C) Dominant gene interaction appears to result in a 9:6:1 ratio. D) Blue-flowering plants are either A_bb or aaB_. E) Analysis of the F1 and F2 progeny phenotypes suggests epistasis.A type of tomato (Solanum lycopersicum) produces fruit in three possible colors: red, green, and orange. You cross a true-breeding orange-fruited plant with a true-breeding green-fruited plant, and all the F1 offspring are red. You intercross the red F1s, and the resulting F2 generation consists of 108 red-, 40 orange-, and 44 green-fruited plants. 1) What type of epistasis is acting (dominant, recessive, duplicate dominant, or duplicate recessive)? 2) Assign the phenotypes to a modified 9:3:3:1 ratio. (Do not just calculate the actual ratio of the phenotypes.) Red : _____Orange : _____Green: _____
- In some plants, a true-breeding, red-flowered variety gives all pink flowers when crossed with a white-flowered strain: RR (red) X rr (white) = Rr (pink). Flower position in this plant may either be axial (dominant) or terminal (recessive). What will be the phenotypic ratios of the F1 generation resulting from the following cross: axial-red (true-breeding) X terminal-white? What will the phenotypic ratios of the F2 be? SHOW ALL WORKYou have two true-breeding strains of coneflower. One strain has purple flowers and purple stems. The other strain has white flowers and green stems. When you cross these strains the F1 generation has purple flowers and purple stems. From this information you know that purple flowers is dominant to white flowers and that purple stems is dominant to green stems. In terms of genetic mechanisms, there could be two explanations: (1) flower color and stem color are each controlled by separate, independently segregating genes, and (2) there is one gene controlling both flower color and stem color. A. If explanation #1 is correct what would you see if the F1 generation were self-crossed to produce an F2 generation. Make up appropriate genetic symbols for this model and work out the cross to the F2 generation. B. If explanation #2 is correct what would you see if the F1 generation were self-crossed to produce an F2 generation. Make up appropriate genetic symbols for this model and work out the…In a test cross, peas of an unknown genotype are crossed with peas of a known genotype. In this example, smooth peas are the unknown and wrinkled peas are the known (rr). If half of the offspring from that cross are smooth and half are wrinkled, what is the genotype of the unknown plant?