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Mod 5- Question 4 Three gases X, Y and Z were mixed in a closed container and allowed to reach equilibrium. A change was imposed at time T and the equilibrium was re-established. The concentration of each gas is plotted against time.

Mod 5- Question 4 Three gases X, Y and Z were mixed in a closed container and allowed to reach equilibrium. A change was imposed at time T and the equilibrium was re-established. The concentration of each gas is plotted against time.

Chemistry by OpenStax (2015-05-04)
Chemistry by OpenStax (2015-05-04)
1st Edition
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter13: Fundamental Equilibrium Concepts
Section: Chapter Questions
Problem 52E: A reaction is represented by this equation: 2W(aq)X(aq)+2Y(aq)Kc=5104 (a) Write the mathematical...
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What causes the large differences in the first steep decrease in all concentrations due to an increase in volume? Why are they different if the coefficients are the same?

Mod 5- Question 4 Three gases X, Y and Z were mixed in a closed container and allowed to reach equilibrium. A change was imposed at time T and the equilibrium was re-established. The concentration of each gas is plotted against time. B. C. D. Concentration (mol L-¹) 0.12 0.10 0.08 0.06 0.04 0.02 X Z Which reaction does the graph represent? XX(g) + Y(g) = 2Z(g) 2X(g) = Y(g) + Z(g) 2X(g) = Y(g) + 3Z(g) X(g) = Y(g) + Z(g) Content Mod 5 Factors that Affect Equilibrium T Time pressure ↓, volume p 2 = x = 1/½/₂24 +2 Syllabus outcomes CH12–5, CH12–12 Bands 5-6 Key D
Transcribed Image Text:Mod 5- Question 4 Three gases X, Y and Z were mixed in a closed container and allowed to reach equilibrium. A change was imposed at time T and the equilibrium was re-established. The concentration of each gas is plotted against time. B. C. D. Concentration (mol L-¹) 0.12 0.10 0.08 0.06 0.04 0.02 X Z Which reaction does the graph represent? XX(g) + Y(g) = 2Z(g) 2X(g) = Y(g) + Z(g) 2X(g) = Y(g) + 3Z(g) X(g) = Y(g) + Z(g) Content Mod 5 Factors that Affect Equilibrium T Time pressure ↓, volume p 2 = x = 1/½/₂24 +2 Syllabus outcomes CH12–5, CH12–12 Bands 5-6 Key D
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