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- A compound bar consisting of bronze, aluminum, and steel segments is loaded axially as shown in the figure. Determine the maximum allowable value of P if the change in length of the bar is limited to 2 mm and the working stresses prescribed in the table are not to be exceeded. Material Properties Material Area(mm2) E (GPa) Normal Stress(MPa) Bronze 450 83 120 Aluminum 600 70 80 Steel 300 200 140 Aluminum 3P Bronze Steel 2P 4P - 0.6 m →- 1.0 m 0.8 mIf the gauge is made of a material having a yield stress equal 200 MPa, determine the minimumrequired diameter d. Using a factor of safety (F.S. = 2)An acetal polymer block is fixed to the rigid plates at its top and bottom surfaces. If the top plate displaces 4 mm horizontally when it is subjected to a horizontal force P = 2 kN, determine the shear modulus of the polymer. The width of the block is 100 mm. Assume that the polymer is linearly elastic and use small angle analysis. 400 mm P=2 kN 200 mm
- The block shown is made of a magnesium alloy for which E=X2GPaand ϑ=0.35. Knowing that σx= X1 MPa, determine (a) the magnitude of σyfor which the change in the height of the block will be zero, (b) the corresponding change in the area of the face ABCD, (c) the corresponding change in the volume of the block.A cylindrical specimen made of annealed 4135 steel has a diameter of 16 cm and is 12 cm high. It is upset, at room temperature, by open-die forging with flat dies to a height of 4.5 cm. Assuming that the coefficient of friction is 0.23, calculate the upsetting force (forging force) required at the end of the stroke. Take material properties, K=1015 MPa, n=0.17.what is the formula used in the -δp + δt = -δp + δt = -δp + δt part at the top? what is the difference between the δp and δt? Why do they have different solutions in the following line of working?
- 1.5-6 The data shown in the table were obtained from a tensile test of a metal specimen with a diameter of 0.500 inch and a gage length (the length over which the elongation is measured) of 2.00 inches. The specimen was not loaded to failure. d. Estimate the value of the proportional limit. e. Use the 0.2% offset method to determine the yield strength. Elongation (in.) Load (kips) 872236 DIN 2.5 3.5 5 7 8 9 10 11.5 12 0 0.0010 0.0014 0.0020 0.0024 0.0036 0.0044 0.0050 0.0060 0.0070 0.0080 0.0120 0.0180The failure stress of a homogeneous steel bar having a diameter of 10 mm is 250 MPa. Using a factor of safety of 2.0 and if the elastic mođulus and length of the bar is 200 GPa and 2 m respectively, calculate the elongation in mm of the bar corresponding to the maximum load it can support. (А) 5 (в) 2.5 1.25 D) 0.625If the gauge is made of a material having a yield stress equal 200 MPa, determine theminimum required diameter d. Using a factor of safety (F.S. = 2)
- (a) 128.5 GPa circular rod of diameter 30 mm and length 200 mm is subjected to a tensile force. The axtension of rod is 0.09 mm and change in diameter is 0.0045 mm. What is the Poisson's ratio of the material of the rod? (a) 0.35 (b) 0.33 (c) 0.32 (d) 0.30Q.1 The yield stresses (oy) have been measured using steel and aluminum specimens of various grain sizes, as follows: Material D (µm) σΥ (MPa) Steel 60.5 160 136 128 Aluminum 11.1 235 100 223 (a) Determine the coefficients o and kỵ in the Hall- Petch for these two materials. (b) Determine the yield stress in each material for a grain size of d=26 um.If the gauge is made of a material having a yield stress equal to 200 Mpa, determine the minimum required diameter d. Using a Factor of safety (F.S=2)