Momo with mass m is sliding down an inclined plane that makes an angle o re to the horizontal. The coefficient of kinetic friction between Momo and the incl plane is µk. Obtain an expression for Momo's acceleration along the incline. Assign a rotated Cartesian plane so that the acceleration is along the positive > and the normal force is along the positive y-axis. The component of the weight parallel to Momo's acceleration is wx = mg Ф. The magnitude of the frictional force is f = uk The normal force on Momo is n = mg Ф. With these expressions and applying Newton's second law, we arrive at an expression for Momo's acceleration:

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Chapter5: More Applications Of Newton’s Laws
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Momo with mass m is sliding down an inclined plane that makes an angle re
to the horizontal. The coefficient of kinetic friction between Momo and the incl
plane is µk. Obtain an expression for Momo's acceleration along the incline.
Assign a rotated Cartesian plane so that the acceleration is along the positive >
and the normal force is along the positive y-axis.
The component of the weight parallel to Momo's acceleration is wx = mg
Ф.
The magnitude of the frictional force is f = µk
The normal force on Momo is n = mg
Ф.
With these expressions and applying Newton's second law, we arrive at an
expression for Momo's acceleration:
a =
- Hk
Transcribed Image Text:Momo with mass m is sliding down an inclined plane that makes an angle re to the horizontal. The coefficient of kinetic friction between Momo and the incl plane is µk. Obtain an expression for Momo's acceleration along the incline. Assign a rotated Cartesian plane so that the acceleration is along the positive > and the normal force is along the positive y-axis. The component of the weight parallel to Momo's acceleration is wx = mg Ф. The magnitude of the frictional force is f = µk The normal force on Momo is n = mg Ф. With these expressions and applying Newton's second law, we arrive at an expression for Momo's acceleration: a = - Hk
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