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My teacher said that the equation v(t) for Vcap (in image) will be V = -1/C integral of i(t) + v(initial). My question is, my teacher has said that the '-' infront of the 1/C is because the current flows into the negative terminal of the capacitor. But in the answer my teacher has put v(initial) as +20 and not -20, even though the 20V across the capacitor is also negative to positive as shown in the image. So why is the v(initial) put as +20 and not -20? Thank you.

My teacher said that the equation v(t) for Vcap (in image) will be V = -1/C integral of i(t) + v(initial). My question is, my teacher has said that the '-' infront of the 1/C is because the current flows into the negative terminal of the capacitor. But in the answer my teacher has put v(initial) as +20 and not -20, even though the 20V across the capacitor is also negative to positive as shown in the image. So why is the v(initial) put as +20 and not -20? Thank you.

Power System Analysis and Design (MindTap Course List)
Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter3: Power Transformers
Section: Chapter Questions
Problem 3.30P: Reconsider Problem 3.29. If Va,VbandVc are a negative-sequence set, how would the voltage and...
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My teacher said that the equation v(t) for Vcap (in image) will be V = -1/C integral of i(t) + v(initial). My question is, my teacher has said that the '-' infront of the 1/C is because the current flows into the negative terminal of the capacitor. But in the answer my teacher has put v(initial) as +20 and not -20, even though the 20V across the capacitor is also negative to positive as shown in the image. So why is the v(initial) put as +20 and not -20? Thank you.
1.6+ MF. Vcop اد +20v It=o T No + BB
Transcribed Image Text:1.6+ MF. Vcop اد +20v It=o T No + BB
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