balance the reactions NalO3(aq)+ Nal,→ Nal3(aq)(aq)Fe+HCI →HFeCl4 (aq) +Fe(OH)2()(aq)+ H₂O2(aq)-H2(g)→ Fe(OH)3()(in HI)(in KOH)

The unbalanced reactions given are NaIO3 (aq) + NaI (aq) →NaI3 (aq) Fe (s) + HCl (aq) →HFeCl4 (aq)…

Answered: NalO3 (q) + Nal (q) → Nal3 (9) Fe +…

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NalO3 (q) + Nal (q) → Nal3 (9) Fe + HCl()→ HFeC14(q) + H2(g) Fe(OH)2 + H₂O2(g) → Fe(OH)3 (in HI) (in KOH)

General, Organic, and Biological Chemistry

7th Edition

ISBN:9781285853918

Author:H. Stephen Stoker

Publisher:H. Stephen Stoker

Chapter10: Acids, Bases, And Salts

Section: Chapter Questions

Problem 10.26EP: The formula for tartaric acid is preferably written as H2C4H4O6 rather than as C4H6O6. Explain why.

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Question

balance the reactions

NalO3
(aq)
+ Nal,
→ Nal3(aq)
(aq)
Fe+HCI →HFeCl4 (aq) +
Fe(OH)2()
(aq)
+ H₂O2(aq)
-H2(g)
→ Fe(OH)3()
(in HI)
(in KOH)

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