Normalize the relations into 3NFORDERSITЕM | ITEM_NUM DESCRIP6531 | Таре7890 Table7956 Pens3456 Stove4234 Paper7956 PensORDERIDDATECUST_CUST_NAMESTATEQUANTITYIDPRICE10017/7A004 George VA100.001400.0012.0010027/8A999BenPÅ1300.0010037/9A201TomPA15234.001020.00

Normalize the relations into 3NF ORDERS ORDER_ ID DATE CUST_ ID CUST_ NAME STATE ITEM ITEM_ _NUM DESCRIP QUANTITY PRICE 1001 7/7 A004 George VA 6531 Tape 5 100.00 7890 Table 7956 Pens 3456 Stove 4234 Paper 7956 Pens 400.00 2.00 300.00 1 7/8 7/9 1002 A999 Ben PA 1 1003 A201 Tom РА 15 234.00 10 20.00 1.

Normalize the relations into 3NF ORDERS ORDER_ ID DATE CUST_ ID CUST_ NAME STATE ITEM ITEM_ _NUM DESCRIP QUANTITY PRICE 1001 7/7 A004 George VA 6531 Tape 5 100.00 7890 Table 7956 Pens 3456 Stove 4234 Paper 7956 Pens 400.00 2.00 300.00 1 7/8 7/9 1002 A999 Ben PA 1 1003 A201 Tom РА 15 234.00 10 20.00 1.

A Guide to SQL

9th Edition

ISBN:9781111527273

Author:Philip J. Pratt

Publisher:Philip J. Pratt

Chapter7: Database Administration

Section: Chapter Questions

Problem 7CAT

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DCIT184 STAT181 Closely examine the following tables and use it to answer the questions that follow: department student_type student_category id |name | location | contact id name id name Computer Science Mathematics Statistics Sociology 005 | History English Linguistic North Ave 1 | +233234545453 North Ave 2 | +233234564554 North Ave 3 001 002 1 | Regular 2| Distance 3 | Sandwich 1 | Foreign 2| Local 003 +233285475547 004 East Ave 4 +233264638374 East Ave 2 +233244454744 006 East Ave 3 +233245653443 007 East Ave 4 +233268888888 course code | title dept_id | credit CSIT205 Object Oriented Techniques For IT Problem Solving Applied IT Programming Database Fundamentals Office Productivity Tools Programming Fundamentals Introduction to History History of The Gold Coast Introduction To Basic Statistics CSIT206 3 CSIT207 DCIT103 DCIT104 HIST101 5 | 3 HIST103 3 STAT101 Student id first_name last_name dob contact stud_cat_id | stud_type_id e0000001 Stephen Amankwah 1999-01-12 +233456789021 1…
The following database will be used in this question: SALESREP SalesRepNo 654 734 345 434 RepName Jones Smith Chen Johnson HireDate 01/02/2005 02/03/2007 01/25/2004 11/23/2004 CUSTOMER CustNo 9870 8590 7840 4870 CustName Winston Gonzales Harris Miles Balance 500 350 SalesRepNo 345 434 654 345 800 100
Insert the following data into your database tables.STUDENTSSTUDENT_ID STUDENT_NAME STUDENT_SURNAMES123456 Neo PetleleS246810 Derek MooreS369121 Pedro NtabaS654321 Thabo JoeS987654 Dominique WoolridgeMODULESMODULE_ID MODULE_NAME MODULE_CREDITDATA6212 Database Intermediate 30INPU221 Desktop Publishing 20PROG6211 Programming 2A 15PROG6212 Programming 2B 15WEDE220 Web Development (Intermediate) STUDENT_MODULESSTUDENT_ID MODULE_IDS123456 PROG6211S123456 PROG6212S246810 DATA6212S369121 DATA6212S369121 INPU221S369121 WEDE220S987654 PROG6211S987654 PROG6212S987654 WEDE220LECTURERSLECTURER_ID LECTURER_NAME LECTURER_SURNAMEL578963 Kwezi MbeteL876592 Julia RobinsL916482 Trevor JanuaryLECTURER_MODULESMODULE_ID LECTURER_IDDATA6212 L578963INPU221 L876592PROG6211 L916482PROG6212 L916482WEDE220 L876592Correct INSERT statements used and all data correctly inserted per table.
Consider the following relation: TempID 111 222 333 444 555 666 TempName Joe Mike Sue Pat Bob Joe TemplD JobID J111 J222 J333 J444 J555 J666 TempName TEMP AGENCY Job TypelD T1 T2 T1 JobID T2 T1 T2 Job TypeDesc Bookkeepiing Answering calls Bookkeepiing Answering calls Bookkeepiing Answering calls • Each job has one job type, but multiple jobs can have the same job type • Each job is assigned to one employer. Same employer can have multiple jobs. 5a) In the figure below, indicate functional dependencies by drawing lines with arrows. -| Some of the requirements that this table is based on are as follows: • Each temporary worker has a unique TempID, and a non-unique TempName. • Each employer has a unique EID, and a non-unique EName. • Each job has a unique JobID, and a job type. • Each job type has a unique JobTypeID and a non-unique job type description (JobTypeDesc). • Each temporary worker is assigned to only one job. EID E1 E1 E2 E2 E2 E1 Job TypeID Job TypeDesc Ename Mid Bank Mid Bank…
3. In the OrderItems table, display a count of the number of products, grouped by prod_id. Display the count with the alias shown. Sort by prod_id in ascending order. BNBG01 BNBG02 BNBG03 BRO1 BRO2 BRO3 RGANO1 7 rows returned in 0.01 seconds PROD_ID Download 3 3 3 2 1 4 2 NUM_PROD_ID
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Use Mysql code The database has three tables for tracking horse-riding lessons: Horse with columns: ID - primary key RegisteredName Breed Height BirthDate Student with columns: ID - primary key FirstName LastName Street City State Zip Phone EmailAddress LessonSchedule with columns: HorseID - partial primary key, foreign key references Horse(ID) StudentID - foreign key references Student(ID) LessonDateTime - partial primary key Write a SELECT statement to create a lesson schedule for Feb 1, 2020 with the lesson date/time, student's first and last names, and the horse's registered name. Order the results in ascending order by lesson date/time, then by the horse's registered name. Make sure unassigned lesson times (student ID is NULL) appear in the results. Hint: Perform a join on the LessonSchedule, Student, and Horse tables, matching the student IDs and horse IDs.
The relational database below contains two related tables - “Supplier” and “Product”: “Product” table: Primary key = Prod-code, Foreign key = Supp-code Prod-code Prod -name Prod -desript Prod -stocktype Prod -stocklevel Prod -expireDate Supp-code 10010 aaa qwert 615 123445677 2017-11-14 501 10011 bbb asdfgg 615 234567899 2017-11-16 501 10012 ccc zxxcvv 234 345678900 2017-11-13 502 10013 eee ytuytu 234 454577777 2017-10-13 503 10014 jjj werewr 231 436436885 2017-10-23 503 10015 sdg rtyrtyry 275 676446322 2017-10-30 504 10016 ewt erterter 789 232317879 2017-12-30 501 “Supplier” table: Primary key = Supp -code, No Foreign key Supp -code Supp -lname Supp -fname Supp -Initial Supp -areacode Supp -phone 501 xxx qwert F 615 123445678 502 yyy asdfgg B 615 234567890 503 zzz zxxcvv X 234 345678901…
Qno 2: Normalize the following Customer-Order Relation up to 3rd Normal Form, but step by step show each intermediate resultant table with its data InvoicelD 601 602 603 InvoiceDate CustID 14/06/09 C_101 14/06/09 C_101 14/06/09 C_102 CUSTOMER-ORDER Table CustName ItemID ItemName ItemQty ItemPrice Naveed 1 Scanner 50 $10 2 Mouse 100 3 Printer 40 2 Mouse 50 4 Monitor 40 Naveed Amjad Scanner 40 $20 $10 $20 $10 $10 InvoiceTotal $2500 $400 $1800
The relational database below contains two related tables - “Supplier” and “Product”: “Product” table: Primary key = Prod-code, Foreign key = Supp-code Prod-code Prod -name Prod -desript Prod -stocktype Prod -stocklevel Prod -expireDate Supp-code 10010 aaa qwert 615 123445677 2017-11-14 501 10011 bbb asdfgg 615 234567899 2017-11-16 501 10012 ccc zxxcvv 234 345678900 2017-11-13 502 10013 eee ytuytu 234 454577777 2017-10-13 503 10014 jjj werewr 231 436436885 2017-10-23 503 10015 sdg rtyrtyry 275 676446322 2017-10-30 504 10016 ewt erterter 789 232317879 2017-12-30 501 “Supplier” table: Primary key = Supp -code, No Foreign key Supp -code Supp -lname Supp -fname Supp -Initial Supp -areacode Supp -phone 501 xxx qwert F 615 123445678 502 yyy asdfgg B 615 234567890 503 zzz zxxcvv X 234 345678901…
true/false INNER JOIN combines two relations. It takes the second relation, and appends it to the end of the first relation. In Corelated Subqueries, subquery is executed independent of the outer query: subquery is executed only once. SELECT * FROM sys.Relations displays information about all the user-defined relations within a database. Given GENDER and STUDENT relations, SELECT Gender, FName, LName FROM GENDER LEFT OUTER JOIN STUDENT ON STUDENT.GenderCode = GENDER.GenderCode ≡ SELECT Gender,FName, LName FROM STUDENT RIGHT OUTER JOIN GENDER ON STUDENT.GenderCode = GENDER.GenderCode The statements select RIGHT('I wish I had attended the practice hours', 9) and select…