P = I R (1) avg rms' V. peak V. (2) rms V, (3) rms I, rms Substitute into (1). Can also use: V2 Pane rms R

University Physics Volume 2
18th Edition
ISBN:9781938168161
Author:OpenStax
Publisher:OpenStax
Chapter12: Sources Of Magnetic Fields
Section: Chapter Questions
Problem 12.8CYU: Check your Understanding Repeat the calculations from the previous example for I0=0.040A .
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An AC power source produces a 170 V peak emf at 70 Hz.  How do you determine the average power dissipated in a 480 ohms resistor connected across this source?  I need help in connecting the attached to the problem better, as you are more conceptually attuned.

P = I R (1)
avg
rms'
V.
peak
V.
(2)
rms
V,
(3)
rms
I,
rms
Substitute into (1).
Can also use:
V2
Pane
rms
R
Transcribed Image Text:P = I R (1) avg rms' V. peak V. (2) rms V, (3) rms I, rms Substitute into (1). Can also use: V2 Pane rms R
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