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- Quinine ( C20 H24 N2 O2) is the most important alkaloid derived from cinchona bark. It is used as an antimalarial drug. For quinine, pK, = 5.1 and pK, = 9.7 ( pKp = – log Kp). Only 1 g quinine will dissolve in 1920.0 mL of solution. Calculate the pH of a saturated aqueous solution of quinine. Consider only the reaction | Q+ H2O= QH+ + OH- described by pK, where Q = quinine. pH =A base is added to a 0.050 M solution of MnCl2, raising the pH gradually. Calculate the pH of the solution when 88 of the manganese has precipitated? Table 5-7 Solubility-Product Constants, K, at 25°C Fluorides Chromates (cont.) Ag, Cro, PbCro, Hydroxides (cont) Ni(OH), Zn(OH), Cu(OH), Hg(OH), Sn(OH), Cr(OH), A(OH), BaF, MgF, PbF, SrF, CaF, 2.4 x 10-5 X 10-8 x 10-8 1.9 x 10-12 1.6 x 10-16 4.5 X 10-17 1.6 x 10-19 3 2 x 10-16 4 Carbonates 7.9 x 10-10 3.9 x 10-11 X 10-26 NiCO, CaCO, BaCo, SrCO, CuCO, ZnCO, MnCO, 1.4 x 10-7 3 10-27 4.7 x 10- 6.7 x 5 x 6 x 10-38 2.5 x 10-43 Chlorides 10-31 1.6 x 10- 1.7 x 10-10 1.1 x 10-18 1.6 x 10-9 7 x 10-10 2.5 x 10-10 10-33 PBCI, AgCi Hg,Cl, Fe(OH), Co(OH), Sulfides 2 x 10-10 8.8 x 10-11 2.1 x 10-11 Bromides X 10-16 X 10-19 3 x 10-21 X 10-22 2.5 x 10-22 X 10-26 1.0 x 10-28 MnS 7. PbBr, AgBr Hg, Br, 4.6 x 10-6 5.0 x 10-13 Feco Ag,CO, CdCo, PBCO, MgCO, Hg,CO, Fes 4 8.2 x 10-12 5.2 x 10-12 1.5 x 10-15 1 x 10-15 NiS 1.3 x 10-22 Cos ZnS lodides Pbl, Agl…Guanosine (C10H13N5O5) in solution has a maximum absorbance at a wavelength of 275 nm. The molar extinction co-efficient at this wavelength is 84M−1cm−1and the path length is 24.7 cm. Through the use of a spectrophotometer, it is found that the that A275= 1.48. What is the concentration of the guanosine solution in grams/litre? Molecular weights (g/mol): C-12, H-1, N-14, O-16 Select one: A. 0.201869 g/L B. 0.435188 g/L C. 0.059919 g/L D. 0.294046 g/L E. 0.000713 g/L
- Calculate the concentration of Y4-ion in 0.0100 M EDTA solution at pH 6. α4 = 2.2 x 10-5 for pH 6.A 10.00-mL aliquot of unknown oxalic acid solution required 15.44 mL of 0.011 17 M KMnO4 solution to reach the purple end point. A blank titration of 10 mL of similar solution containing no oxalic acid required 0.04 mL to exhibit detectable color. Find the concentration of oxalic acid in the unknown.A base is added to a 0.050 M solution of MnCl2, raising the pH gradually. Calculate the pH of the solution when 70 of the manganese has precipitated? Table 5-7 Solubility-Product Constants, K, at 25°C Fluorides Chromates (cont.) Ag, Cro, PbCro, Hydroxides (cont.) Ni(OH), Zn(OH), Cu(OH), Hg(OH)2 Sn(OH), Cr(OH), Al(OH), Fe(OH), Co(OH), Sulfides Baf, MGF2 PbF, SrF, CaF, 2.4 x 10-6 1.9 x 10-12 1.6 x 10-16 8 x 10-8 X 10-8 7.9 x 10-10 3.9 x 10-11 2 x 10-16 4.5 X 10-17 4 1.6 x 10-19 X 10-26 X 10-27 6.7 x 10-31 Carbonates NiCO, CaCO, BaCO, SrCO, CuCO, ZnCO, MNCO, FeCo, Ag,CO, CdCo, PbCO, M9CO, Hg,CO, 1.4 X 10-7 4.7 x 10-9 3. Chlorides 1.6 x 10-9 PbCl, AgCI Hg,Cl, х 10-33 X 10-38 2.5 x 10-43 1.6 x 10-5 X 10-10 2.5 x 10-10 2 x 10-1o 8.8 x 10-11 2.1 X 10-11 7 1.7 x 10-10 1.1 X 10-18 6. Bromides PbBr2 X 10-16 X 10-19 X 10-21 5 x 10-22 2.5 x 10-22 X 10-26 1.0 x 10-28 MnS 4.6 x 10-6 5.0 x 10-13 Fes 4. AgBr Hg,Br, 8.2 x 10-12 NiS Cos Zns 1.3 x 10-22 3 5.2 x 10-12 1.5 x 10-15 1 x 10-15 9.0 x 10-15…
- Calculate the concentration of Y4-ion in 0.0100 M EDTA solution at pH 6. for pH 6, α4 = 2,2 x 10-5at 257 nm) is dissolved in 2.5 mL of buffer. A 250 microliter aliquot is removed and placed in a 1.0 cm A sample of adenosine triphosphate (ATP) (MW 507, ɛ = 14,700 M'cm cuvette with sufficient buffer to give a total volume of 2.0 mL. The absorbance of the sample at 257 nm is 2.0. Calculate the weight of ATP in the original 2.5 mL sample. (Choose the correct value from the drop-down list provided. The values of weight are listed in units of milligrams.) Weight of ATP: v mgWhat mass of sodium glycolate (NaC2H3O3) should be added to 400.0 mL of 1.00 M glycolic acid to produce a buffer solution with a pH of 4.00? Ka = 1.47 x 10-4. Please indicate the full solutions.
- How much caffeine can be extracted using 50.0ml of DCM if a tea bag contains 15 grams of tea leaves with 0.9% of caffeine? And has undergone solid-liquid extraction with 100ml of distilled water followed by liquid-liquid extraction using DCM. The solubility of caffeine requires 15 ml of water and 2.0ml of DCM for 40.0mg.You need a buff er at pH 7.5 for use in purifying a protein at 4°C. You have chosen Tris, pK 8.08, ΔH° = 50 kJ · mol−1. You carefully make up 0.01 M Tris buffer, pH 7.5 at 25°C, and store it in the cold to equilibrate it to the temperature of the purifi cation. When you measure the pH of the temperature-equilibrated buff er it has increased to 8.1. What is the explanation for this increase? How can you avoid this problem?Lactic acid 4 g Salicylic acid 5 g Trichloroacetic acid 2 g Flexible collodion qs ad 100 g Sig: wart remover. Use as directed (a) Flexible collodion contains 20% w/w camphor and 30% w/w castor oil. How many grams of each would be contained in 30 g of the mixture? (b) The specific gravity of castor oil is 0.955. H ow many milliliters of the oil is contained in 30 g of the mixture? (c) If the specific gravity of the mixture is 0.781, what are the percent w/v concentrations of lactic acid, salicylic acid, and trichloroacetic acid in the mixture? Answer: (a) 5.34 g camphor and 8.01 g castor oil (b) 8.39 mL castor oil (c) 3.12% w/v lactic acid, 3.91% w/v salicylic acid, and 1.56% w/v trichloroacetic acid Solution of the given answer is needed. Thank you so much and God bless. Happy new year