• Part C Find the maximum force the spring exerts on the glider. Express your answer with the appropriate units. HA ? Fmax =- 69.92 %3D

University Physics Volume 1
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ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:William Moebs, Samuel J. Ling, Jeff Sanny
Chapter15: Oscillations
Section: Chapter Questions
Problem 59AP: The device pictured in the following figure entertains infants while keeping them from wandering....
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Part C
Find the maximum force the spring exerts on the glider.
Express your answer with the appropriate units.
Fmax =
- 69.92
N
Transcribed Image Text:Part C Find the maximum force the spring exerts on the glider. Express your answer with the appropriate units. Fmax = - 69.92 N
On a frictionless, horizontal air track, a glider oscillates at the
end of an ideal spring of force constant 2.30 N/cm The
graph in the figure (Figure 1) shows the acceleration of the
glider as a function of time.
Part A
Find the mass of the glider.
For related problemsolving tips and strategies, you may want
to view a Video Tutor Solution of Angular frequency,
frequency, and period in shm
Express your answer with the appropriate units.
?
m= 5.83
kg
Figure
1 of 1>
Part B
Find the maximum displacement of the glider from the equilibrium point.
az (m/s³)
Express your answer with the appropriate units.
12.0
?
6.0
t (s)
0/10 0.20 030 0.40
A = 0.304
-6.0
-12.0
Transcribed Image Text:On a frictionless, horizontal air track, a glider oscillates at the end of an ideal spring of force constant 2.30 N/cm The graph in the figure (Figure 1) shows the acceleration of the glider as a function of time. Part A Find the mass of the glider. For related problemsolving tips and strategies, you may want to view a Video Tutor Solution of Angular frequency, frequency, and period in shm Express your answer with the appropriate units. ? m= 5.83 kg Figure 1 of 1> Part B Find the maximum displacement of the glider from the equilibrium point. az (m/s³) Express your answer with the appropriate units. 12.0 ? 6.0 t (s) 0/10 0.20 030 0.40 A = 0.304 -6.0 -12.0
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